Assuming that you meant "x - 4y = 20", the x-intercept is x=20, and the y-intercept is y=-5.
Ah, let's paint a happy little picture with this equation. To find the x-intercept, we set y to 0 and solve for x. So, -10x = -20, which gives us x = 2. For the y-intercept, we set x to 0 and solve for y. So, -10y = -20, which gives us y = 2. And just like that, we've found our x-intercept at (2, 0) and y-intercept at (0, 2).
It is an equation and the value of x is 20
5x6 = 30 -10 = 20.
z = 20 (6x20) + (5x20) = 20
Solve the equation for y. This will give you an equation similar to y = ax + b, where a is the slope, and b is the y-intercept.
Is the equation of a straight line with slope 2 and an intercept of (0,20).
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
If you put this equation in y-intercept form it is y=4/3x+20 If you have a graphing calculator just enter this in "y=" or graph it manually to find the x-intercept.
== == y = -x + 5
5x+4y = 20 4y = -5x+20 y = -5/4x+5 Therefore: slope is -5/4 and intercept is 5
write equation in standfrd form y =mx + b where b = y intercept 5x - 2y =20 5x -20 = 2y 5/2 x -10 = y when x = 0 y = -10, the y intercept
To find the x-intercept, set y equal to zero in the equation 5x + 2y = 20. Then solve for x: 5x + 2(0) = 20. Simplifying, 5x = 20. Dividing both sides by 5, x = 4. Therefore, the x-intercept is (4, 0).
5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.
If you mean: -5x+2y = 20 then the x intercept is -4 and the y intercept is 10
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
Slope= -2/5 y-intercept is 20 x-intercept is 50