x - 3 = y
-- At the x-intercept, y=0.
x - 3 = 0
x = 3
The x-intercept is the point (3, 0).
-- At the y-intercept, x=0.
0 -3 = y
y = -3
The y-intercept is the point (0, -3).
The coordinates of the x intercept for the equation y equals x plus 1 is (x=-1, y=0).
The x-intercept is (15 0)
x-intercept = (-6, 0)
2y = 4x + 3At the x-intercept, y=0.0 = 4x + 34x = -3x = -3/4The coordinates of the point are (-3/4 , 0)
-10
The coordinates of the x intercept for the equation y equals x plus 1 is (x=-1, y=0).
x-intercept = (-6, 0)
The x-intercept is (15 0)
(4,0)
-10
They are at coordinates of: (0, -6) and (15, 0) respectively
2y = 4x + 3At the x-intercept, y=0.0 = 4x + 34x = -3x = -3/4The coordinates of the point are (-3/4 , 0)
5x - 2y = 20The x-intercept of a line is the point where its y-value is 0. When y=0, we get 5x = 20, or x=4. This means the coordinates of the x-intercept on this line are (4,0).
solve for x -x-2y=6 -x=2y+6 x=-2y-6 plug in y=0 x=-6 when y is 0 therefore the x intercept is (-6,0)
I think they will intercept
-10
-5x + 6y = 30At the x-intercept, y=0:-5x = 30 ==> x = -6At the y-intercept, x=0:6y = 30 ==> y = 5