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The resistors are 5, 10, and 15 ohms.

The current through the 5-ohm resistor is E/R = 15/5 = 3 Amp.

The current through the 10-ohm resistor is E/R = 15/10 = 1.5 Amp.

The current through the 15-ohm resistor is E/R = 15/15 = 1 Amp.

Their total effective resistance in parallel is the reciprocal of [ (1/5) + (1/10) + (1/15) ] =

the reciprocal of [ (6/30) + (3/30) + (2/30) ] = the reciprocal of [ (11/30) ] = 30/11 ohms .

The total current drawn from the battery is E/R = (15)/(30/11) = (15 x 11/30) = 11/2 = 5.5 Amp.

Note:

The 5-ohm resistor is dissipating 45 watts.

The 10-ohm resistor is dissipating 22.5 watts.

The 15-ohm resistor is dissipating 15 watts.

The poor battery is delivering 82.5 watts.

None of this is going to last very long at all.

Most likely, the battery has already expired,

and/or the 5-ohm resistor has already exploded,

while we've been here playing with our calculators.

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Q: What is the current of each resistor and the total current drawn from the battery of a 5 ohm resistor 10 ohm resistor and a 15 ohm resistor in parallel connected to a 15 volt battery?
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