1/h-8 = (1/h)-8 = h8
The derivative of a constant is always 0. To show this, let's apply the definition of derivative. Recall that the definition of derivative is: f'(x) = lim h→0 (f(x + h) - f(x))/h Let f(x) = 1. Then: f'(x) = lim h→0 (1 - 1)/h = lim h→0 0/h = lim h→0 0 = 0!
You can easily derive it from formula for the derivative of a power, if you remember that the cubic root of x is equal to x1/3. This question asks for the proof of the derivative, not the derivative itself. Using the definition of derivative, lim f(x) as h approaches 0 where f(x) = (f(a+h)-f(a))/h, we get the following: [(a+h)1/3 - a1/3]/h Complete the cube with (a2 + ab + b2) Multiply by [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] This completes the cube in the numerator, resulting in the following: (a + h - a) / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h cancels 1 / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] Now that we have a function that is continuous for all h, we can evaluate the limit by plugging in 0 for h. This gives 1/[a2/3 + a1/3 × a1/3 + a2/3] Simplify a1/3 × a1/3 1/[a2/3 + a2/3 + a2/3] (1/3)a2/3 or (1/3)a-2/3 This agrees with the Power Rule.
The derivative of f(x) is lim h-->0 [f(x+h)-f(x)]/h. So let f(x) = -5x. The derivative is lim h-->0 [-5(x+h)- -5(x)]/h = lim h-->0 [-5x - 5h + 5x]/h = lim h-->0 -5h/h Since the limit h-->0 of h/h is 1, the derivative is -5
f'(g(h(x)))*g'(h(x))*h'(x) where the prime denote a derivative with respect to x.
The derivative of any expression is the rate at which it changes. A constant, such as a number made from digits, doesn't change, so its derivative is zero. 485 is a constant. It doesn't change, so its derivative (the rate at which it changes) is zero. You can also take any constant, call it c, and apply the definition of a derivative using limits. Lim as h goes to 0 of {f(x+h)-f(x)}/h becomes lim as h goes to 0 of (c-c)/h which is 0
h3/h8 = h-5 = 1/h5
If vector A has constant magnitude, then its derivative will be tangent to the direction of vector A. Since the derivative is perpendicular to the tangent vector, it will be perpendicular to vector A. This is because the derivative represents the rate of change of vector A with respect to time, which is perpendicular to the direction of a vector with constant magnitude.
G is always negative when H is negative and S is positive.
The spacial derivative is the measure of a quantity as and how it is being changed in space. This is different from a temporal derivative and partial derivative.
Hydroxide (OH-) has a negative charge because it has gained an extra electron, giving it a net negative charge of -1. This extra electron is acquired when a hydrogen ion (H+) is donated to the hydroxide ion as part of a chemical reaction.
Hulk and the Agents of S-M-A-S-H- - 2013 Into the Negative Zone 1-12 was released on: USA: 17 November 2013