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d/dh(h^-1) = -1(h^-2) = -(h^-2)

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What is 1 over h to the negative 8 power?

1/h-8 = (1/h)-8 = h8


What is the derivitive of 1?

The derivative of a constant is always 0. To show this, let's apply the definition of derivative. Recall that the definition of derivative is: f'(x) = lim h→0 (f(x + h) - f(x))/h Let f(x) = 1. Then: f'(x) = lim h→0 (1 - 1)/h = lim h→0 0/h = lim h→0 0 = 0!


What is the Proof of the derivative of the third root of x?

You can easily derive it from formula for the derivative of a power, if you remember that the cubic root of x is equal to x1/3. This question asks for the proof of the derivative, not the derivative itself. Using the definition of derivative, lim f(x) as h approaches 0 where f(x) = (f(a+h)-f(a))/h, we get the following: [(a+h)1/3 - a1/3]/h Complete the cube with (a2 + ab + b2) Multiply by [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] This completes the cube in the numerator, resulting in the following: (a + h - a) / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h / (h × [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3]) h cancels 1 / [(a+h)2/3 + (a+h)1/3 × a1/3 + a2/3] Now that we have a function that is continuous for all h, we can evaluate the limit by plugging in 0 for h. This gives 1/[a2/3 + a1/3 × a1/3 + a2/3] Simplify a1/3 × a1/3 1/[a2/3 + a2/3 + a2/3] (1/3)a2/3 or (1/3)a-2/3 This agrees with the Power Rule.


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h3/h8 = h-5 = 1/h5


Prove that if vector A has constant magnitude then its derivative is perpendicular to vector A?

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Why does hydroxide have a negative charge?

Hydroxide (OH-) has a negative charge because it has gained an extra electron, giving it a net negative charge of -1. This extra electron is acquired when a hydrogen ion (H+) is donated to the hydroxide ion as part of a chemical reaction.


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