The derivative of f(x) is
lim h-->0 [f(x+h)-f(x)]/h.
So let f(x) = -5x. The derivative is
lim h-->0 [-5(x+h)- -5(x)]/h
= lim h-->0 [-5x - 5h + 5x]/h
= lim h-->0 -5h/h
Since the limit h-->0 of h/h is 1, the derivative is
-5
You will find several formulae in the Wikipedia article on "derivative".
The purpose of finding a derivative is to find the instantaneous rate of change. In addition, taking the derivative is used in integration by parts.
To find the derivative of ( \frac{3}{\sqrt{x}} ), we can rewrite it as ( 3x^{-\frac{1}{2}} ). Using the power rule, the derivative is ( -\frac{3}{2} x^{-\frac{3}{2}} ). This can also be expressed as ( -\frac{3}{2\sqrt{x^3}} ).
2 x 2 = 4. 4 is a constant. The derivative of a constant is always 0. Therefore, The derivative of 2 x 2 is zero.
we have to find out dy/dx of sinx0 ----
The derivative of sin(x) is cos(x).
You take the derivative using only one variable. The other variables act as constants.
To find the derivative of a function with terms 2, 4, 6, and 8 without using integration, you would differentiate each term separately using the power rule. The power rule states that for a term of the form axn, the derivative is nax(n-1). Apply this rule to each term to find the derivative of the function.
You will find several formulae in the Wikipedia article on "derivative".
The derivative at any point in a curve is equal to the slope of the line tangent to the curve at that point. Doing it in terms of the actual expression of the curve, find the derivative of the curve, then plug the x-value of the point into the derivative to find the derivative at that point.
Find the derivative of Y and then divide that by the derivative of A
The derivative of x^n is nx^(n-1) any n. The derivative of x^4 is 4x^3.
The purpose of finding a derivative is to find the instantaneous rate of change. In addition, taking the derivative is used in integration by parts.
All it means to take the second derivative is to take the derivative of a function twice. For example, say you start with the function y=x2+2x The first derivative would be 2x+2 But when you take the derivative the first derivative you get the second derivative which would be 2
Find the derivative
Afetr you take the first derivative you take it again Example y = x^2 dy/dx = 2x ( first derivative) d2y/dx2 = 2 ( second derivative)
This is really too vague. There are tables for derivatives of common functions. There are rules for taking derivatives of polynomials. The derivative of f(x) is found by taking the limit of (f(x + ?x) - f(x))/?x, as ?x approaches zero.