D(y)= sin 2x
x=2
the answer is eight equals two times for
Which means 0 = -1!
parallel
y = -1/(3x7 + 2x - 9)y = -(3x7 + 2x - 9)-1y' = -(-1)(3x7 + 2x - 9)-2(3x7 + 2x - 9)'y' = (3x7 + 2x - 9)-2(21x6 + 2)y' = (21x6 + 2)/(3x7 + 2x - 9)2
y=2x y-2x=0 or 2x-y=0
I am interpreting this as: Find the derivative of: y=((2x+5)8+4x)3 To find the derivative (y'), the chain rule must be applied. The "outermost" function of this compound function is t3 (t being an arbitrary quantity). The derivative of t3 is 3t2 * dt, where "dt" is the derivative of the quantity "t". Applying this, we arrive at a working definition of y': y' = 3((2x+5)8+4x)2(derivative of (2x+5)8+4x) The derivative of (2x+5)8+4x is found using basic derivative definitions and the chain rule again: 8(2x+5)7(2)+4 = 16(2x+5)7+4 So now we can write y' again: y'= 3((2x+5)8+4x)2(16(2x+5)7+4) = 48((2x+5)8+4x)2((2x+5)7+4) This can be further simplified, but this is an arduous process. If you need further simplification, feel free to contact me via private message.
y = 2x
They are parallel lines
y= -2x
7