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y=5-2x
y'(u-v)=du/dx-dv/dx
y'(5-2x)=d/dx(5)-d/dx(2x)
-The derivative of 5 is 0 because it's a constant.
-The derivative of 2x is:
d/dx(cu)=c*du/dx where c is a constant.
d/dx(2x)=2*d/dx(x)
y'(5-2x)=(0)-[2*d/dx(x)]
-The derivative of x is:
d/dx(xn)=nxn-1
d/dx(x)=1*x1-1
d/dx(x)=1*x0
d/dx(x)=1*(1)
d/dx(x)=1
y'(5-2x)=-[2*(1)]
y'(5-2x)=-(2)
y'(5-2x)= -2
Derivative of sin x = cos x, so chain rule to derive 8x = 8 , answer is 8cos8x
Because the derivative of e^x is e^x (the original function back again). This is the only function that has this behavior.
Calculate the derivative of the function.Use the derivative to calculate the slope at the specified point.Calculate the y-coordinate for the point.Use the formula for a line that has a specified slope and passes through a specified point.
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Well, isn't that a happy little question! To find the derivative of x divided by y, you can use the quotient rule. The derivative will be (y * d/dx(x) - x * d/dx(y)) / (y^2). Just remember, there are no mistakes, just happy little accidents in math!