57.3062 ft
134.6 feet
53.85164807' by means of Pythagoras.
A rectangle doesn't have a hypotenuse.The diagonal of this one is sqrt(6,100) = 78.1025 (rounded)
Width would be 14 cm
To answer the question as written: If the length of a rectangle is given as being 50 feet, then the length of the rectangle is 50 feet. To answer the question that is really being asked, if the width of a rectangle is 12.4 feet and the length of 50 feet, the area can be found by multiplying the length by the width. Therefore, the are of the rectangle would be 620 square feet. If however, the question was to determine the perimeter, you would use the formula 2l+2w=p so you would add 12.4 +12.4+50+50, for a perimeter of 124.8 feet.
134.6 feet
Use Pythagoras' theorem:- 502+302 = 3400 and the square root of this is the length of the diagonal which is about 58.309 feet to 3 dp
53.85164807' by means of Pythagoras.
50
A rectangle doesn't have a hypotenuse.The diagonal of this one is sqrt(6,100) = 78.1025 (rounded)
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
Width would be 14 cm
To answer the question as written: If the length of a rectangle is given as being 50 feet, then the length of the rectangle is 50 feet. To answer the question that is really being asked, if the width of a rectangle is 12.4 feet and the length of 50 feet, the area can be found by multiplying the length by the width. Therefore, the are of the rectangle would be 620 square feet. If however, the question was to determine the perimeter, you would use the formula 2l+2w=p so you would add 12.4 +12.4+50+50, for a perimeter of 124.8 feet.
15 feet
IF the area is a rectangle, then150 x 50 = 7,500 square feet
If that's a rectangle or a kite, then the perimeter is 50 feet.
It works out as: 90 feet Check: 2*(90+50) = 280 feet