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2x plus y equals 5 2y plus x equals 4?
2x + y = 5 2y + x = 4 This is SIMULTANEOUS Equations. To solve , arbitrarily select a letter to eliminate, In this case 'x' To do this the coefficients of 'x' must be the same , but of opposite sign. Hence multiply the bottom equation by '-2' Hence 2x + y = 5 -2x - 4y = =8 Add -3y = -3 Divide both sides by '-1' 3y = 3 y = 1 When y= 1 Substitute back in to either eq'n 2x + 1 = 5 Subtract '1' from both sides 2x = 4 x = 2 Hence the answer is ( x,y) = ( 2,1)
How do you substitute x plus y equals 5 and x equals y plus 1?
Eq 1: + y= 5 Eq 2: x = y + 1 substitute y + 1 for x in equqtion 1 y+1 + y = 5 2y + 1 = 5 2 y = 4 y = 2 substitute 2 for y in eq 2 x = 2 + 1 x = 3
What is x-2y equals 0 in 4x-3y equals 15?
eq. 1 is x-2y=0 which means x=2y eq. 2 is 4x-3y=15 subst. x=2y in eq. 2 4(2y)-3y=15 8y-3y=15 5y=15 y=3 subst. y=3 in eq. 1 we get x=2(3) x=6 Ans: x=6 and y=3 is the required solution. Thank you.
How do you write the equation of a line that passes through the point 4 and -2 and has a slope of 2?
The standard form eqaution for a line is y = mx + b where m = slope and b is y intercept ( value of y when x = 0) if x = 4 and y = -2 and m = 2 then y = mx + b (eq 1) -2 = 2 (4) + b -2 = 8 + b -10 = b substitute into eq (1): y = 2x-10
You are trying to figure out the difference in transmissions for your 61 rancheroA 3 speed with the numbers code70064 and dif 6 on the side 4 bolt top cover found another trans same code diff dif 2?
The people at www.drivetrain.com may be able to help you figure it out. Hope this helps.
Solve the following system of equation algebraically 3xplus2y equals 4 4xplus 3y equals 7?
3x + 2y = 4 (Eq 1); 4x + 3y = 7 (Eq 2) Eliminate x Eq 1 x 4 = 12x + 8y = 16 (Eq 3) Eq 2 x 3 = 12x + 9y = 21 (Eq 4) Subtract Eq 3 from Eq 4 y = 5 so x = (4 - 10)/3 = -6/3 ie -2 Check Eq 2: (4 x -2) + (3 x 5) = -8 + 15 = 7 QED
If 4 plus 4 equals 3 what is 9 plus 9?
see if 4+4=3 then value of 3=4+4 (eq 1) now we need to find out 9+9=? we can write 9+9 as 3+3+3+3+3+3 (eq 2) now by substituting the value of 3 from eq 1 in eq 2 we will get (4+4)+(4+4)+(4+4)+(4+4)+(4+4)+(4+4)=48 so 9+9=48
Solve the simultaneous equations 4x plus 3y equals -5 3x plus 5y equals -12?
4x + 3y = -5 (Eq 1); 3x + 5y = -12 (Eq 2) Eliminate x Eq 1 times 3: 12x + 9y = -15 Eq 2 times 4: 12x +20y = -48 Subtract Eq 1 from Eq 2 11y = -48-(-15) ie 11y = -33 y = -3 Substitute in Eq 1: 4x - 9 = -5, ie 4x = 4 so x = 1 Check in Eq 2: (3 x 1) + (5 x -3) = 3 - 15 = -12. QED
How do you solve the system of equasions x y z-10 2x 4y 2z-32 and-x 8y-3z-42?
Assuming the equations are: x + y. + z = 10 1 2x + 4y + 2z =32 2 -x +8y - 3z = 42 3 Multiply eq 3 by 2 and add to eq 2: 20y -4z = 116 4 Multiply eq 1 by 2 and subtract it from eq 2: 2y = 12; then y = 6 Substitute in eq 4: Then -4z = 116 - 120 = -4; z = 1 Substitute in eq 1; then X = 10 - 6 - 1 = 3 Answer: X = 3 Y = 6 Z = 1
Use the substitution method to solve the system of equations Enter your answer as an ordered pair 16x - 2y equals 74 2x - 2y equals 4?
16x - 2y = 74 (Eq 1) 2x - 2y = 4 (Eq 2) from Eq 2, 2y = 2x - 4 Substitute in Eq 1 16x - (2x - 4) =74 ie 16x - 2x + 4 = 74 ie 14x = 70 ie x = 5 2y = 2x - 4 = 10 - 4 = 6 y =3 Check 16 x 5 - 2 x 3 = 80 - 6 = 84 QED
2 door speakers do you need a 4 channel amp?
No that would be a 2 channel amp. 1 speaker per channel. 2 speakers= 2 channels 4 speakers= 4 channels
What is a channel in amplifier mean?
a channel refers to the speakers or subs. for example a 2 channel amp can power 2 subs or speakers. a 4 channel will power 4.
What is the value of x and y in the simultaneous equation 4x plus 3y equals -5 and 3x plus 5y equals -12?
4x + 3y = -5 (Eq 1) 3x + 5y = -12 (Eq 2) Multiply the first equation by 3 and the second by 4: 12x + 9y = -15 (Eq 3) 12x + 20y = -48 (Eq 4) subtract Eq 3 from Eq 4 gives 11y = -33 so y = -3 and x = (15 + 12)/3 =1 Check: (4 x 1) + (3 x -3) = 4 - 9 = -5 and (3 x 1) + (5 x -3) = 3 - 15 = -12 QED Subtract
Yes you can bridge this amplifier to a 2 channel at 4 ohm per channel for 200 watts out of each channel.?
Yes you can bridge this amplifier to a 2 channel at 4 ohm per channel for 200 watts out of each channel.
How do you substitute x plus y equals 5 and x equals y plus 1?
Eq 1: + y= 5 Eq 2: x = y + 1 substitute y + 1 for x in equqtion 1 y+1 + y = 5 2y + 1 = 5 2 y = 4 y = 2 substitute 2 for y in eq 2 x = 2 + 1 x = 3
2x plus y equals 5 2y plus x equals 4?
2x + y = 5 2y + x = 4 This is SIMULTANEOUS Equations. To solve , arbitrarily select a letter to eliminate, In this case 'x' To do this the coefficients of 'x' must be the same , but of opposite sign. Hence multiply the bottom equation by '-2' Hence 2x + y = 5 -2x - 4y = =8 Add -3y = -3 Divide both sides by '-1' 3y = 3 y = 1 When y= 1 Substitute back in to either eq'n 2x + 1 = 5 Subtract '1' from both sides 2x = 4 x = 2 Hence the answer is ( x,y) = ( 2,1)
What is x-2y equals 0 in 4x-3y equals 15?
eq. 1 is x-2y=0 which means x=2y eq. 2 is 4x-3y=15 subst. x=2y in eq. 2 4(2y)-3y=15 8y-3y=15 5y=15 y=3 subst. y=3 in eq. 1 we get x=2(3) x=6 Ans: x=6 and y=3 is the required solution. Thank you.
