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There is no difference in meaning between the two. It is usually spelled in lowercase, though (arc tan, or arctan).
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What is the value of x in Arc tanx 5pidivided by 4?
1 because tan(5 pi / 4) = 1
What are the alternative ways of finding the length of the hypotenuse of a right angle triangle without using Pythagoras theorem?
The least accurate is to draw the triangle and then measuring it. Alternatively you can use trigonometric ratios: tan = opposite/adjacent sin = opposite/hypotenuse → hypotenuse = opposite/sin cos = adjacent/hypotenuse → hypotenuse = adjacent/cos Using the tangent ration one of the non-right angles of the triangle can be found. Then using either the sine or cosine ratio the hypotenuse can be found. eg if the two "legs" are 1 cm and √2 cm, then: The angle at the end of the √2 cm side is: arc tan(1/√2) = 30° Then the hypotenuse is: 1 cm / sin (arc tan(1/√2)) = 1 cm / ½ = 2 cm. or √2 / cos (arc tan(1/√2)) = √2 / (1/√2) = √2 × √2 = 2. eg if the two "legs" are 3 cm and 4 cm, then: The angle at the end of the 4 cm side is: arc tan ¾ ≈ 36.87° The the hypotenuse is: 3 / sin(arc tan ¾) = 3/0.6 = 5 or 4 / cos(arc tan ¾) = 3/0.8 = 5
What are the functions and classification in calculus?
1.4 Classification Of FunctionsAnalytically represented functions are either Elementary or Non-elementary.The basic elementary functions are :1) Power function :y = xm , m ÎR2) Exponential function :y = ax , a > 0 but a ¹ 13) Logarithmic function :y = log ax , a > 0, a ¹ 1 and x > 04) Trigonometric functions :y = sin x, y = cos x, y = tan x,y = csc x, y = sec x and y = cot x5) Inverse trigonometric functionsy = sin-1 x, y = cos-1x, y = tan-1x,OR y = cot-1x, y = cosec-1x, y = sec-1x.y = arc sin x, y = arc cos x, y = arc tan xy = arc cot x, y = arc csc x and y = arc sec x
What is the difference between sinx and tanx?
Sin = Opposite/Hypotenuse, tan = Opposite/Adjacent
How do you calculate arc length given length of chord and distance of chord to arc through the center?
It is much easier to follow what is below if you have a rough sketch. Suppose the length of the chord is 2x units so that half the chord is x units. Suppose that the distance from the centre of the circle to the arc = y units. Suppose the angle subtended at the centre by the chord is 2k radians. Then the semi-chord and the line from the centre form a right angled triangle with the radius to the end of the chord, and the angle subtended by the semi-chord at the centre is k radians. Now, by Pythagoras the radius, r = sqrt(x2 + y2) units and tan(k) = x/y (or sin(k) = x/r Since both x and y are given, r and k can be calculated. Then arc length = r*k which is a simple multiplication. If you measure angles in degrees, remember that pi radians = 180 degrees.
What is the limit of arc tan?
The principal range of arc tan is an angle in the open interval (-pi/2, pi/2) radians = (-90, 90) degrees.
What is the angle between a line of a graph and a positive direction of the x-axis?
The angle is the arc-tan of the gradient of the line. That is to say, the tangent of that angle is the gradient of the line or the angle between the straight line and the positive x-axis. Arc tan may also be written as tan-1 but that is frequently confused with 1/tan or the cotangent function.
What is the value of Arc-tan of 49.22?
Arctan (49.22) = 88.83608° or 1.55048 radians.
What is the derivative of arc tan x?
d/dx(arctan x) = X = 1/(1 + x2)
What is the value of x in Arc tanx 5pidivided by 4?
1 because tan(5 pi / 4) = 1
What are the alternative ways of finding the length of the hypotenuse of a right angle triangle without using Pythagoras theorem?
The least accurate is to draw the triangle and then measuring it. Alternatively you can use trigonometric ratios: tan = opposite/adjacent sin = opposite/hypotenuse → hypotenuse = opposite/sin cos = adjacent/hypotenuse → hypotenuse = adjacent/cos Using the tangent ration one of the non-right angles of the triangle can be found. Then using either the sine or cosine ratio the hypotenuse can be found. eg if the two "legs" are 1 cm and √2 cm, then: The angle at the end of the √2 cm side is: arc tan(1/√2) = 30° Then the hypotenuse is: 1 cm / sin (arc tan(1/√2)) = 1 cm / ½ = 2 cm. or √2 / cos (arc tan(1/√2)) = √2 / (1/√2) = √2 × √2 = 2. eg if the two "legs" are 3 cm and 4 cm, then: The angle at the end of the 4 cm side is: arc tan ¾ ≈ 36.87° The the hypotenuse is: 3 / sin(arc tan ¾) = 3/0.6 = 5 or 4 / cos(arc tan ¾) = 3/0.8 = 5
What are the functions and classification in calculus?
1.4 Classification Of FunctionsAnalytically represented functions are either Elementary or Non-elementary.The basic elementary functions are :1) Power function :y = xm , m ÎR2) Exponential function :y = ax , a > 0 but a ¹ 13) Logarithmic function :y = log ax , a > 0, a ¹ 1 and x > 04) Trigonometric functions :y = sin x, y = cos x, y = tan x,y = csc x, y = sec x and y = cot x5) Inverse trigonometric functionsy = sin-1 x, y = cos-1x, y = tan-1x,OR y = cot-1x, y = cosec-1x, y = sec-1x.y = arc sin x, y = arc cos x, y = arc tan xy = arc cot x, y = arc csc x and y = arc sec x
What are the polar coordinates?
What are polar coordinates of (√2, 1)? Solution: Here we need to convert from rectangular coordinates to polar coordinates: P = (x, y) = (r, θ) r = ± √(x^2 + y^2); tan θ = y/x or θ = arc tan (y/x) So we have: P = (√2, 1) r = ± √[(√2)^2 + 1^2] = ± √3 θ = arc tan (y/x) = arc tan (1/√2) = arc tan (√2/2) ≈ 35.3°, which is one possible value of the angle. (√2, 1) is in the Quadrant I. If θ = 35.3°, then the point is in the terminal ray, and so r = √3. Therefore polar coordinates are (√3, 35.3°). Another possible pair of polar coordinates of the same point is (-√3, 215.3°) (180° + 35.3° = 215.3°). Edit: Note the negative in the r value.
What is the difference between tan and swift bic?
What is the difference between tan number and swift bic ?
Does mass warp space?
No! This is Einstein's General Relativity Theory. It is not correct. Einstein's deflection angle 1.7" is the result of plain old Newton's Gravity Theory, not space warp. The distance from the sun is Rs=150Gm and the gravity of the earth is 9.8, c is the speed of light, the time is t=Rs/c = 500 secs. The deflection angle is ARC Tan y/Rs = .5gt^2/150Gm = ARC Tan .5 x9.8x(500)^2/150G The result is ARC Tan 8.16666E-6 and angle 1.68". The gravity of earth 9.8 m/s^2 is the cause of the deflection not space warp. This says that light has mass.
What is tangent inverse of -1.6?
arc tan -1.6 ≈ -57.99 + 180n degrees ≈ -1.01 + nπ radians ≈ -64.44 + 200n gradians.
What is a good calculator for trigonometry?
Any calculator sold as a "scientific calculator" has the basic trigonometric functions (sin, cos, tan) and the inverse trigonometric functions (arc-sin, arc-cos, arc-tan). That's about all you need.You can also use the calculator that comes on your computer - for example, in Windows, press Windows-R, and then type "calc". You may have to change the calculator mode, to "scientific calculator". Yet another option is a spreadsheet, for example, Excel. Note that in Excel, angles are expressed in radians; if you want degrees, you also need the special functions to convert degrees to radians, or radians to degrees. However, if you want to do your homework while you are NOT at your computer, you are better off buying a calculator.
