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What is the derivative of secant x?
The derivative of sec(x) is sec(x) tan(x).
When does cos x equal -sin x?
Cos (x) = -Sin(x) 1 = -Sin(x) / Cos (x) 1 = -Tan(x) Tan(x) = -1 x = Tan^-1(-1( x = -45 degrees = - pi /4 , 3pi/4, 5pi/4 ....
What is the angle between a line of a graph and a positive direction of the x-axis?
The angle is the arc-tan of the gradient of the line. That is to say, the tangent of that angle is the gradient of the line or the angle between the straight line and the positive x-axis. Arc tan may also be written as tan-1 but that is frequently confused with 1/tan or the cotangent function.
What is the derivative of 1 over x?
Derivative of 1/x 1/x = x-1 Take the derivative (-1)x(-1-1) = -x-2 = 1/x2
What is the answer to cot squared x - tan squared x equals 0?
cot2x-tan2x=(cot x -tan x)(cot x + tan x) =0 so either cot x - tan x = 0 or cot x + tan x =0 1) cot x = tan x => 1 / tan x = tan x => tan2x = 1 => tan x = 1 ou tan x = -1 x = pi/4 or x = -pi /4 2) cot x + tan x =0 => 1 / tan x = -tan x => tan2x = -1 if you know about complex number then infinity is the solution to this equation, if not there's no solution in real numbers.
What is the derivative of tan x?
The derivative of tan(x) is sec2(x).(Which is the same as 1/cos2(x).
What is the derivative of secant x?
The derivative of sec(x) is sec(x) tan(x).
What is the derivative of y equals sec x?
sec(x)tan(x)
What is the derivative of cscx?
d/dx csc(x) = - csc(x) tan(x)
What is the derivative of tan x0 its x to the power 0?
Regardless of what 'x' is, (x)0 = 1 . tan(1 radian) = 1.55741 (rounded) tan(1 degree) = 0.01745 (rounded) We can't remember the derivative of the tangent right now, but it doesn't matter. This particular tangent is a constant, so its derivative is zero.
When does cos x equal -sin x?
Cos (x) = -Sin(x) 1 = -Sin(x) / Cos (x) 1 = -Tan(x) Tan(x) = -1 x = Tan^-1(-1( x = -45 degrees = - pi /4 , 3pi/4, 5pi/4 ....
What is the derivative of inverse tangent of x?
d/dx[ tan-1(x) ] = 1/(1 + x2)
What is the derivative of ln cos x?
The derivative of the natural log is 1/x, therefore the derivative is 1/cos(x). However, since the value of cos(x) is submitted within the natural log we must use the chain rule. Then, we multiply 1/cos(x) by the derivative of cos(x). We get the answer: -sin(x)/cos(x) which can be simplified into -tan(x).
What is the derivative of y equals tan x?
Given y = tan x: dy/dx = sec^2 x(secant of x squared)
What is the difference between Arc tan and arc tan?
There is no difference in meaning between the two. It is usually spelled in lowercase, though (arc tan, or arctan).
What is the derivative of secxtanx?
d/dx(uv)=u*dv/dx+v*du/dxd/dx(secxtanx)=secx*[d/dx(tanx)]+tanx*[d/dx(secx)]-The derivative of tanx is:d/dx(tan u)=[sec(u)]2*d/dx(u)d/dx(tan x)=[sec(x)]2*d/dx(x)d/dx(tan x)=[sec(x)]2*(1)d/dx(tan x)=(sec(x))2=sec2(x)-The derivative of secx is:d/dx(sec u)=[sec(u)tan(u)]*d/dx(u)d/dx(sec x)=[sec(x)tan(x)]*d/dx(x)d/dx(sec x)=[sec(x)tan(x)]*(1)d/dx(sec x)=sec(x)tan(x)d/dx(secxtanx)=secx*[sec2(x)]+tanx*[sec(x)tan(x)]d/dx(secxtanx)=sec3(x)+sec(x)tan2(x)
What is the angle between a line of a graph and a positive direction of the x-axis?
The angle is the arc-tan of the gradient of the line. That is to say, the tangent of that angle is the gradient of the line or the angle between the straight line and the positive x-axis. Arc tan may also be written as tan-1 but that is frequently confused with 1/tan or the cotangent function.
