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What is the dimensions of a rectangular surface when the length is 10 feet more than the width and the area is equal to 144?
Wiki User
∙ 14y ago
Let the width be x and the length be x+10:
x(x+10) = 144 square feet
Multiply out the brackets and bring over 144 to the LHS which will give you a quadratic equation to solve:
x2+10x-144 = 0
Factorising the equation:
(x+18)(x-8) = 0
Therefore: x = -18 or x = 8
Obviously x must be 8
So the dimensions are: width = 8 feet and length = 18 feet
Wiki User
∙ 14y ago
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