What is the distance between -3 2and 5 -1?

Answer 1

Apply Pythagoras

d^(2) = (x^(2) + y^(2)

Hence for the points (-3,2)& ( 5. -1)

d^(2) = (-3-5)^(2) + (2 - - 1)^(2) (Note the double minus).

d^(2) = (-8)^(2) + (3)^(2)

d^(2) = 64 + 9

d^(2) = 73

d = sqrt(73)

d = 8.54400....

Answer 2

To find the distance between the points (-3, 2) and (5, -1), you can use the distance formula: (d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}). Substituting the coordinates, we get (d = \sqrt{(5 - (-3))^2 + (-1 - 2)^2} = \sqrt{(5 + 3)^2 + (-3)^2} = \sqrt{8^2 + (-3)^2} = \sqrt{64 + 9} = \sqrt{73}). Thus, the distance between the two points is (\sqrt{73}), which is approximately 8.54.