To find the distance between the points (-3, 2) and (5, -1), you can use the distance formula: (d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}). Substituting the coordinates, we get (d = \sqrt{(5 - (-3))^2 + (-1 - 2)^2} = \sqrt{(5 + 3)^2 + (-3)^2} = \sqrt{8^2 + (-3)^2} = \sqrt{64 + 9} = \sqrt{73}). Thus, the distance between the two points is (\sqrt{73}), which is approximately 8.54.
The distance is 4
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
7.2111 (rounded)
Distance between (1, 3) and (-1, 0.5) = sqrt[(1 - -1)2 + (3 - 0.5)2] = sqrt(22 + 2.52) = sqrt(10.25) = 3.20 approx.
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
2.2
(0,2)
4
The distance is 4
3-4 = -1 -21 the distance between -1 and -21 is -20 -20 -1 = -21
The factors of 2 are 1 and 2. The factors of 3 are 1 and 3. The only common factor is 1.
4.
3 and 1/2 miles
3 and 1/2 miles
3+5+7+9+11=35
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
7.2111 (rounded)