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Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1):

distance = √(change_in_x² + change_in_y²)

→ distance = √((x1 - x0)² + (y1 - y0)²)

→ distance = √((4 - 1)² + (-1 -2)²)

→ distance = √(3² + (-2)²)

→ distance = √(9 + 9)

→ distance = √18 = 3 √2

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More answers

It is 3*sqrt(2).

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8y ago
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Q: What is the distance between points 1 2 and 4 -1?
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