Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
Points: (2, 1) and (14, 6) Distance: 13
If you mean points of (-4, 2) and (1, 2) then the distance works out as 5
The distance between the points can be calculated by using the difference in the x coordinates, the difference in the y coordinates and Pythagoras. distance = sqrt((difference_in_x_coords)2 + difference_in_y_coords)2) So for the points (-1, 1) and (1, -1) the distance between them is: sqrt((-1 - 1)2 + (1 - -1)2) =sqrt(22 + 22) =sqrt(4 + 4) = sqrt(8) ~= 2.83
The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
11 points
Points: (-6, 1) and (-2, -2) Distance: 5 units
Answer: 1
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
Distance = (9-5)2+(-6-1)2 = 65 and the square root of this is the distance between the points which is about 8.062257748
The distance between the points can be calculated by using the difference in the x coordinates, the difference in the y coordinates and Pythagoras. distance = sqrt((difference_in_x_coords)2 + difference_in_y_coords)2) So for the points (-1, 1) and (1, -1) the distance between them is: sqrt((-1 - 1)2 + (1 - -1)2) =sqrt(22 + 22) =sqrt(4 + 4) = sqrt(8) ~= 2.83
The shortest distance between the two points is zero
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
8.54
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
If you mean points of (2, 4) and (-1, 8) then the distance works as 5
If you mean points of: (2, 1) and (14, 6) then the distance is 13