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What is the distance between the points -30 -10 and -30 18 in the xy plane?
Wiki User
∙ 11y ago
18 - (-10) = 18 + 10 = 28 units.
Wiki User
∙ 11y ago
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What is the distance between the points (45) and (1013) on a coordinate plane?
If you mean points of (4, 5) and (10, 13) then the distance works out as 10
What is the distance between the points (4 5) and (10 13) on a coordinate plane?
10 units
What is the distance between the points (-2 16) and (8 16) in the xy-plane?
10 units.
What is the distance between the points named by -3 1 and -7 1 on the coordinate plane?
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
What is the distance between the points (22) and (8-6)?
Points: (2, 2) and (8, -6) Distance: 10
What is the distance between the points (45) and (1013) on a coordinate plane?
If you mean points of (4, 5) and (10, 13) then the distance works out as 10
What is the distance between the points (4 5) and (10 13) on a coordinate plane?
10 units
What is the distance between the points (-2 16) and (8 16) in the xy-plane?
10 units.
What is the distance between the points (45) and (103) on a coordinate plane?
The distance between (4, 5) and (10, 3) = sqrt(40) = 2*sqrt(10) = 6.3246 approx.
What is the distance between the points named by -3 1 and -7 1 on the coordinate plane?
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
on a coordinate plane, what is the distance between the point (-2, -3) and (-2, 10)?
If you mean points of (5, 5) and (1, 5) then the distance is 4
Find the distance between these points A32 B910?
If the points are (3, 2) and (9, 10) then the distance works out as 10
What is the distance between the points (22) and (8-6)?
Points: (2, 2) and (8, -6) Distance: 10
Find the distance between the points-2 -10 and -8 -2?
10
What is the distance between the point (45) and (1013) on a coordinate plane?
If you mean (4, 5) and (10, 13) then the distance is 10
What is the distance between the points (10 12) and (4 36)?
The distance between points can be calculated using Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((4 - 10)² + (36 - 12)²) → distance = √((-6)² + (24)²) → distance = √(36 + 576) → distance = √612 → distance = 6 √17 ≈ 24.74 units.
What is the distance between the points -6-10 and 25?
If you mean points of: (-6, -10) and (2, 5) then it works out as 17
