If you mean points of: (-6, -10) and (2, 5) then it works out as 17
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If you mean points of: (2, 5) and (-4, 8) Distance is the square root of (2--4)^2+(5-8)^2 = 6.708 rounded
For two coordinates points (x1, y1) and x2, y2), you can find the straight line distance using the Pythagorean theorem.The vertical difference (y1-y2) forms one side of the triangle, and the horizontal difference is the other (x2-x1). The hypotenuse is the straight distance along the line, and is defined by :h = square root of (a2 plus b2) = square root of [ (y2-y1)2 + (x2-x1)2 ]---EXAMPLE :For points (1, 3) and (4, 7), the distance along y is (7-3) and along x is (4-1) andsquare root [ 42 + 32 ] = sq rt [9 + 16] = sq rt [25] = 5.Measuring the distance along the line would verify that the distance is 5.
Use trigonometry to find the distance of each boat from the cliff's base and subtracting both distances gives a distance of 40.5 meters between them to 1 d.p.
I'm assuming that these are 3-D coordinates A(0,0,0) and B(3,4,5) The distance formula between two points in 3 dimensions is the following: D = SQR {(x1-x2)2 + (y1-y2)2 + (z1-z2)2} D = SQR {(0-3)2 + (0-4)2 + (0-5)2} D = SQR {9+16+25} = SQR {50} D is approx. = 7.07
P( 8,2) & Q( 3,8) Apply Pythagoras. d^2 = (8 - 3)^2 + ( 2 - 8)^2 d^2 = 5^2 + (-6)^2 d^2 = 25 + 36 d^2 = 61 d = sqrt(61) ~ 7.81 (2 d.p.