Earth is part of our solar system.
6 - the same as from 4 to 10.
6 is closer to 10 (4 away) than it is to zero (6 away).
The distance between points can be calculated using Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((4 - 10)² + (36 - 12)²) → distance = √((-6)² + (24)²) → distance = √(36 + 576) → distance = √612 → distance = 6 √17 ≈ 24.74 units.
End points: (10, -4) and (2, 2) Midpoint: (6, -1) Distance from (6, -1) to (10, -4) = 5 Distance from (6, -1) to (2, 2) = 5 Equation of the circle: (x-6)^2 +(y+1)^2 = 25
14
The distance along a straight line is 10. Using the Pythagorean equation, c2 = a2 + b2 where the x change is 6 and the y change is 8, c2 = 62 + 82 = 36 + 64 = 100 c = [sqrt 100] = 10
Known equation: y = 2x+10 Perpendicular equation: 2y = -x+10 Both equations intersect at: (-2, 6) Distance from (2, 4) to (-2, 6) is sq rt of 20 using the distance formula
(0, 4) and (- 4, 6) ???Distance = sqrt[(Y2 - Y1)2 + (X2 - X1 )2]Distance = sqrt[(6 - 4)2 + (- 4 - 0)2]Distance = sqrt( 4 + 16)Distance = sqrt(20)==============
Distance: square root of [(4-7)squared+(6--3)squared)] = 3 times sq rt of 10 which is about 9.487 rounded
10
10
-4 - 6 = -10