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The distance between the points of (4, 3) and (0, 3) is 4 units
Pythagoras can be used to find the distance between any two points (x0, y0) and (x1, y1): Distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((5 - 5)² + (13 - 9)²) = √(0 + 4²) = √(4²) = 4.
The distance between points: (9, 4) and (3, 4) is 6
(-3-(-6))2 + (7-4)2 = 18 and the square root of this is the distance between the two points
The distance between the points of (4, 3) and (0, 3) is 4 units
Points: (2, 4) and (5, 0) Distance: 5
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5 is.
Since they are the same point, the distance between them is 0.
The distance between the points of (4, 3) and (0, 3) is 4 units
-2 & 5
Pythagoras can be used to find the distance between any two points (x0, y0) and (x1, y1): Distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((5 - 5)² + (13 - 9)²) = √(0 + 4²) = √(4²) = 4.
If you mean: (-8, 4) and (5, 4) Then the distance between the points works out as 13
Distance between (0,0) and (8,2): √((8-0)2+(2-0)2) = √(82+22) = √(64+4) = √(68) = 2√17 ~= 8.246
Distance = sqrt [(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt [(6 - 4)2 + (- 4 - 0)2]Distance = sqrt [(2)2 + (- 4)2]Distance = sqrt(4 + 16)Distance = sqrt(20)==============
The distance between points: (9, 4) and (3, 4) is 6