(0, 4) and (- 4, 6) ???
Distance = sqrt[(Y2 - Y1)2 + (X2 - X1 )2]
Distance = sqrt[(6 - 4)2 + (- 4 - 0)2]
Distance = sqrt( 4 + 16)
Distance = sqrt(20)
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The distance between the points of (4, 3) and (0, 3) is 4 units
Pythagoras can be used to find the distance between any two points (x0, y0) and (x1, y1): Distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((5 - 5)² + (13 - 9)²) = √(0 + 4²) = √(4²) = 4.
The distance between points: (9, 4) and (3, 4) is 6
(-3-(-6))2 + (7-4)2 = 18 and the square root of this is the distance between the two points