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Points: (4, -6) and (2, -3)

Slope: -3/2

Equation: 2y = -3x

Perpendicular slope: 2/3

Perpendicular equation: 3y = 2x+3

Both equations meet at: (-6/13, 9/13)

Distance from (6, 5) to (-6/13, 9/13) is 7.766 units rounded to 3 decimal places

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Q: What is the distance from the point of 6 5 that meets the line of 4 -6 and 2 -3 at right angles on the Cartesian plane giving answer to an appropriate degree of accuracy?
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