d/dt (7s/2t3) = negative 21s/2t4 (ds/dt)
(Not bad for stuff I haven't used in 30 years, eh ?)
y=x3+ 2x, dx/dt=5, x=2, dy/dt=? Differentiate the equation with respect to t. dy/dt=3x2*dx/dt Substitute in known values. dy/dt=3(2)2 * (5) dy/dt=60
Force (F) F = m.a and since a = dv/dt thus F = m.dv/dt Momentum (p) p = m.v and since a = dv/dt thus p = m.a.dt By switch dt from R.H.S. to L.H.S we get dp/dt = m.a thus F = dp/dt
You need to clarify what you want to solve for. If you're solving for z, then we can say: dz/dt + 4et + z = 0 ∴ dz/dt = -4et - z ∴ ∫(dz/dt) dt = -2et2 - zt + C ∴ z = -2et2 - zt + C ∴ z + zt = -2et2 + C ∴ z(1 + t) = -2et2 + C ∴ z = (-2et2 + C) / (1 + t)
Momentum is the quantity that is conserved in this case. Conservation of Momentum is a consequence of Conservation of Energy, which equates to the sum of forces equals zero. 0 = f1 + f2 = dp1/dt + dp2/dt = d(p1 +p2)/dt = d(constant)/dt =0.
The condition for maximum velocity is acceleration equals zero; dv/dt = a= o.
I will assume that you mean to ask, "What is the arc length of curve C from t=0 to t=1 if curve C is defined parametrically by x=1+2e^t and y=e^t?" I can answer this question. dx/dt=2e^t and dy/dt=e^t. Arc length = a∫b √[(dx/dt)2+(dy/dt)^2] = 0∫1 √[4e^(2t)+e^(2t)]dt = 0∫1 √[5e^(2t)]dt. = 0∫1 [(√5)(e^t)]dt = √5 x (e^1-e^0) = √5 x (e-1) = e√5-√5. Difficult? Maybe. Fun? Hopefully. Accurate? Definitely!
y(t) = 3.5 - 3.5*e1-20t Then dy/dt = -3.5*e1-20t*(-20) = 70*e1-20t
Gamma DT is a term used in finance to refer to the gamma of a delta-neutral options position. It measures how the delta changes as the stock price changes.Gamma DT helps traders understand how the position's sensitivity to price movements evolves over time.
The rate of change of flux equals the induced electromotive force or voltage in a circuit, as described by Faraday's law of electromagnetic induction. Mathematically, this relationship is expressed as: (\text{EMF} = -\frac{d\Phi}{dt}), where EMF is the induced voltage, (\Phi) is the magnetic flux, and (\frac{d\Phi}{dt}) is the rate of change of magnetic flux over time.
Rockets work on the conservation of vector energy, cP. 0 = dcP/dr = cdP/cdt=dP/dt = d(mV)/dt = mdV/dt + Vdm/dt=0 Thus, mdV/dt = -Vdm/dt, or (dV/dt)/V = -(dm/dt)/m. The Rocket's mass accelerates at the rate of the mass changes dm/dt.
d/dt cot (t) dt = - cosec2(t)
a = dv/dt =d(vet)/dt =dv/dt *et+det/dt *vwith det =...