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What is derivative of 9et?
Assume that the expression is: y = 9e^(t) Remember that the derivative of e^(t) with respect to t is e^(t). If we take the derivative of the function y, we have.. dy/dt = 9 d[e^(t)]/dt = 9e^(t) Note that I factor out the constant 9. If we keep the 9 in the brackets, then the solution doesn't make a difference.
What is the derivative of t?
If it is with respect to t: 1 If it is with respect to some other variable (x for example): (dt)/(dx), which is literally read "the derivative of t with respect to x"
What is the derivative of cot x?
The derivative of cot(x) is -csc2(x).(Which is the same as -1/sin2(x).)
What is the derivative of csc x?
The derivative of csc(x) is -cot(x)csc(x).
What expression is equivalent to cot t sec t?
Which expression is equivalent to cot t sec t
What is the derivative of x equals cot2 divided by t?
Assuming you want dx/dt and that the equation is x = cot(2) / t (i.e. cot(2) is a constant) we can use the power rule. First, we rewrite it: cot(2)/t = cot(2) * t-1 thus, by the power rule: dx/dt = (-1) cot(2) * t-1 -1 = - cot(2) * t-2= = -cot(2)/t2
Prove that if vector A has constant magnitude then its derivative is perpendicular to vector A?
If vector A has constant magnitude, then its derivative will be tangent to the direction of vector A. Since the derivative is perpendicular to the tangent vector, it will be perpendicular to vector A. This is because the derivative represents the rate of change of vector A with respect to time, which is perpendicular to the direction of a vector with constant magnitude.
What is derivative of 9et?
Assume that the expression is: y = 9e^(t) Remember that the derivative of e^(t) with respect to t is e^(t). If we take the derivative of the function y, we have.. dy/dt = 9 d[e^(t)]/dt = 9e^(t) Note that I factor out the constant 9. If we keep the 9 in the brackets, then the solution doesn't make a difference.
What is the derivative of t?
If it is with respect to t: 1 If it is with respect to some other variable (x for example): (dt)/(dx), which is literally read "the derivative of t with respect to x"
What is the derivative of te(-t2)?
Use the product and chain rules: d/dt te^(-t²) = (d/dt t)e^(-t²) + t(d/dt e^(-t²)) = 1 × e^(-t²) + t × e^(-t²) × d/dt -t² = e^(-t²) (1 + t × -2t) = (1 - 2t²)e^(-t²)
What is the derivative of cot x?
The derivative of cot(x) is -csc2(x).(Which is the same as -1/sin2(x).)
What is the 4th derivative of the position function?
Distance f(x) = x(t) = 1/2at2+vit+xi Velocity f'(x) = v(t) = dx/dt=at +vi Acceleration f''(x) = a(t) = dv/dt Jerk f'''(x) = j(t) = da/dt The fourth derivative is not universally accepted, but some have called it "snap", and the fifth and sixth derivatives "crackle" and "pop" respectively. Snap f(4)(x) = s(t) = dj/dt Crackle f(5)(x) = c(t) = ds/dt Pop f(6)(x) = p(t) = dc/dt
What is the derivative of cot?
d/dx (cot x) = -csc2x
What is intantaeous speed?
If a body is moving at a non-constant speed then its instantaneous speed is the derivative of its displacement with respect to time.If the body is at positions x(t) and x(t+dt) at times t and t+dt then the instantaneous speed at time t is the limit, as dt tends to 0, of [x(t+dt) - x(t)]/t.In graph terms, it is the gradient of tangent to the displacement-time graph.
What is the derivative of cotx?
The derivative of cot(x) is -csc2(x).
How do you prove the derivative of parametric equations?
The question is to PROVE that dy/dx = (dy/dt)/(dx/dt). This follows from the chain rule (without getting into any heavy formalism). We know x and y are functions of t. Given an appropriate curve (we can integrate piece-wise if necessary), y can be written as a function of x where x is a function of t, i.e., y = y(x(t)). By the chain rule, we have dy/dt = dy/dx * dx/dt. For points where the derivative of x with respect to t does not vanish, we therefore have (dy/dt)/(dx/dt) = dy/dx.
What is acceleration of a particle if position of a particle at any instant of time t is given by x equals t 3?
velocity is 1st derivative of distance with respect to time acceleration is 2nd derivative of distance with respect to time dx/dt = velocity = 3t^2 dv/dt = acceleration = 6t
