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x2/242-y2/62=1

Q: What is the equation for a hyperbola that has a transverse axis length of 24 and is centered at the origin?

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you

y2/52 - x2/72 = 1

x^2/11^2 - y^2/5^2

x2/172 - y2/b2 = 1 for some constant b.

True

Related questions

you

x2/242-y2/62=1

y2/52 - x2/72 = 1

x2/172 - y2/b2 = 1 for some constant b.

x^2/11^2 - y^2/5^2

y^2/15^2 - x^2/6^2 = 1

true

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x2/132-y2/152=1

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difference between TPate