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What expression gives the length of the transverse axis of the hyperbola?
The length of the transverse axis of a hyperbola is given by the expression ( 2a ), where ( a ) is the distance from the center of the hyperbola to each vertex along the transverse axis. For a hyperbola centered at the origin with the standard form ( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 ) (horizontal transverse axis) or ( \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 ) (vertical transverse axis), the value of ( a ) determines the extent of the transverse axis. Thus, the transverse axis length varies directly with ( a ).
Which expression gives the length go the transverse axis of the hyperbola shown below?
The length of the transverse axis of a hyperbola is determined by the value of (2a), where (a) is the distance from the center to each vertex along the transverse axis. In the standard forms of hyperbolas, such as ((x-h)^2/a^2 - (y-k)^2/b^2 = 1) or ((y-k)^2/a^2 - (x-h)^2/b^2 = 1), (a) represents this distance. Therefore, to find the length of the transverse axis, you would use the expression (2a).
How do you write an algebraic expression from a real world situation?
2*pi*sqrt(L/g) this expression gives (approximately) the period (in seconds) of a pendulum whose length is L (metres) and g is the acceleration due to gravity = 9.8 metres/second2.
What expression gives the distance between (25) and (-48)?
73
What is the answer to y equals twelve over x?
You cannot solve this single equation. You can either change the subject so that it gives x = 12/y or xy = 12, which is the equation of a rectangular hyperbola.
What expression gives the length of the transverse axis of the hyperbola?
The length of the transverse axis of a hyperbola is given by the expression ( 2a ), where ( a ) is the distance from the center of the hyperbola to each vertex along the transverse axis. For a hyperbola centered at the origin with the standard form ( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 ) (horizontal transverse axis) or ( \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 ) (vertical transverse axis), the value of ( a ) determines the extent of the transverse axis. Thus, the transverse axis length varies directly with ( a ).
Which expression gives the length of the transverse axis of the hyperbola shown below?
a - b
Which expression gives the length go the transverse axis of the hyperbola shown below?
The length of the transverse axis of a hyperbola is determined by the value of (2a), where (a) is the distance from the center to each vertex along the transverse axis. In the standard forms of hyperbolas, such as ((x-h)^2/a^2 - (y-k)^2/b^2 = 1) or ((y-k)^2/a^2 - (x-h)^2/b^2 = 1), (a) represents this distance. Therefore, to find the length of the transverse axis, you would use the expression (2a).
Which expression gives the length of PQ in the triangle shown below?
A triangle has 3 line segments
A skateboard ramp is built with a base length of 30 feet and a height of 13 feet.Which expression gives the value of x?
tan 13/30
How do you write an algebraic expression from a real world situation?
2*pi*sqrt(L/g) this expression gives (approximately) the period (in seconds) of a pendulum whose length is L (metres) and g is the acceleration due to gravity = 9.8 metres/second2.
Which expression gives the distance between the points (0 -1) and (1 -2)?
the area of a rectangle with width x and length 6x is 6x^2 what does the coefficient 6 mean in terms of the problem
What information does the slope of the line in distance-time graph give?
It gives the velocity of the object in the radial direction. The graph gives no information whtsoever about motion in a transverse direction.
What is the solution to 3x over 4x plus 3?
The question gives an expression, not an equation. An expression cannot have a solution.
What expression gives the distance between (25) and (-48)?
73
Is amplitude longitudinal?
Not necessarily. "Amplitude" gives you an idea about how "strong" a wave is; the concept applies both to longitudinal and to transverse waves.
How to find the area fro the perimeter?
What is its area? Divide the perimeter by 4: that gives you the length of one side. Then square that length: that gives you the area.
