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2*pi*sqrt(L/g) this expression gives (approximately) the period (in seconds) of a pendulum whose length is L (metres) and g is the acceleration due to gravity = 9.8 metres/second2.
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You cannot solve this single equation. You can either change the subject so that it gives x = 12/y or xy = 12, which is the equation of a rectangular hyperbola.
length of arc/length of circumference = angle at centre/360 Rearranging the equation gives: length of arc = (angle at centre*length of circumference)/360
It indicates that the object in question is not moving in towards or away from the origin. However, it gives no information about motion in the transverse direction.
a - b
A triangle has 3 line segments
tan 13/30
2*pi*sqrt(L/g) this expression gives (approximately) the period (in seconds) of a pendulum whose length is L (metres) and g is the acceleration due to gravity = 9.8 metres/second2.
the area of a rectangle with width x and length 6x is 6x^2 what does the coefficient 6 mean in terms of the problem
It gives the velocity of the object in the radial direction. The graph gives no information whtsoever about motion in a transverse direction.
The question gives an expression, not an equation. An expression cannot have a solution.
73
Not necessarily. "Amplitude" gives you an idea about how "strong" a wave is; the concept applies both to longitudinal and to transverse waves.
1/2rx
You cannot solve this single equation. You can either change the subject so that it gives x = 12/y or xy = 12, which is the equation of a rectangular hyperbola.
What is its area? Divide the perimeter by 4: that gives you the length of one side. Then square that length: that gives you the area.