R = (density)(Length)/(Area)
Unit of resistance is Ohms.
You don't specify diameter. I am assuming it is the same. However, the larger the wire the lower the resistance. Temperature affects resistance. The hotter the wire, the higher the resistance. You also don't specify the layout of the wire. For example you could make a coil or choke with one wire.
if length is doubled then resistivity increases&when area is doubled resistivity decreases.
There is no formula to calculate the length of a wire. The length of a wire is determined by the distance from the power source to where the load is situated.
When i will be a pro will help
In the standard equation for an ellipse, b is half the length of the _____ axis.Answer:
resistance of wire increases with increases of length
I think the equation you are looking for is Resistance (ohms) = Resistivity * Length / Area or R=p*L/A. This is the resistance of a circular wire with cross-section of A, length of L, and material with resistivity p. So to get area: Area = Resistivity * Length / Resistance.
If the wire's cross-section area is constant, then its resistance per unit length is constant, and the total resistance should be directly proportional to the length of a wire segment.
resistance is directly proportional to wire length and inversely proportional to wire cross-sectional area. In other words, If the wire length is doubled, the resistance is doubled too. If the wire diameter is doubled, the resistance will reduce to 1/4 of the original resistance.
Assuming the wire follows Ohm's Law, the resistance of a wire is directly proportional to its length therefore doubling the length will double the resistance of the wire. However when the length of the wire is doubled, its cross-sectional area is halved. ( I'm assuming the volume of the wire remains constant and of course that the wire is a cylinder.) As resistance is inversely proportional to the cross-sectional area, halving the area leads to doubling the resistance. The combined effect of doubling the length and halving the cross-sectional area is that the original resistance of the wire has been quadrupled.
Work it out for yourself. The equation you will need to use is: resistance = resistivity x (cross-sectional area / length) Manipulate the equation to make 'length' the subject, and use 17.25 x 10-9 ohm metres as the value of resistivity.
You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).You can increase the resistance in the wire, by doing any of the following:Increase the length of the wire.Reduce the wire's cross-section.Change to a material that has a greater resistivity (specific resistance).
Yes, resistance is directly proportional to the length, and inversely proportional to the cross sectional area. R = p*l/A. Where R is the resistance of the piece of conducting material, p is Greek letter rho, representing the resistivity of the material, l (lower case L) is the length, and A is the area.
In general, the longer the wire the greater the resistance. The only time that this is not so is when the wire is a superconductor, in which case the resistance is always zero.
Double the length is double the resistance. Resistance of a wire is the resistivity of the material, times the length, divided by the cross-section area.
the resistance is depends on the type of the metal and ith length
*the resistivity of the metal the wire is made of *thickness of wire *length of wire