xy +7
The product is the result of the multiplication of numbers. In the equation 2 x 3 = 6, 6 is the product of 2 times 3.
As a product of its prime factors: 2*2*2*3*3 = 72
84 = 2*2*3*7
27*28 = 756
It will take six. 2 x 2 x 2 x 2 x 2 x 2 = 64
64 = 2 x 2 x 2 x 2 x 2 x 2 or 26
64 = 2 x 2 x 2 x 2 x 2 x 2 or 26
The answer is 324x. Since there is only 1 x in the equation, just multiply the 2 whole numbers and add the x to the end of the product.
Using the equation 55 x 2 = 110, the numbers are called as follows: multiplicand x multiplier = product.
Let's denote the two consecutive numbers as x and x+1. We know that their product is 1806, so we have the equation x(x+1) = 1806. By expanding the left side, we get x^2 + x = 1806. Rearranging the equation, we have x^2 + x - 1806 = 0. This is a quadratic equation that can be factored as (x - 42)(x + 43) = 0. Therefore, the two consecutive numbers are 42 and 43.
Let the first even number be represented by (2x), where (x) is an integer. The next consecutive even number would then be (2x + 2). The product of these two numbers is (2x(2x + 2) = 4x^2 + 4x). Setting this equal to 840 gives us the quadratic equation (4x^2 + 4x - 840 = 0). Solving this equation yields (x = 10) and (x = -21), but since we are dealing with even numbers, the two consecutive even numbers are 20 and 22.
56 = 2 x 2x 2 x 7 56 = 23 x 7