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Let's denote the two consecutive numbers as x and x+1. We know that their product is 1806, so we have the equation x(x+1) = 1806. By expanding the left side, we get x^2 + x = 1806. Rearranging the equation, we have x^2 + x - 1806 = 0. This is a quadratic equation that can be factored as (x - 42)(x + 43) = 0. Therefore, the two consecutive numbers are 42 and 43.

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ProfBot

4mo ago

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