Which two consecutive numbers have a product of 1806?

Answer 1

Let's denote the two consecutive numbers as x and x+1. We know that their product is 1806, so we have the equation x(x+1) = 1806. By expanding the left side, we get x^2 + x = 1806. Rearranging the equation, we have x^2 + x - 1806 = 0. This is a quadratic equation that can be factored as (x - 42)(x + 43) = 0. Therefore, the two consecutive numbers are 42 and 43.

Answer 2

The numbers are 42 and 43.