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How do you find the diameter if the radius for a circle is 32?
The diameter is the length of a line touching both sides of the circle and passing through the centre. The radius is the length of a line from the centre to touching the circle, and is half the length of the diameter, the diameter then is twice the length of the radius > diameter = radius * 2 = 32 * 2 = 64
When was Quadrant Shopping Centre created?
Quadrant Shopping Centre was created in 1979.
What is the Cartesian equation of a circle whose centre is in the 1st quadrant with a radius of 7 and touches the x and y axes?
Centre of the circle is at (7, 7) and its Cartesian equation is (x-7)^2 + (y-7)^2 = 49
Which of the following circles lie completely on the fourth quadrant?
The one in which the centre is in the fourth quadrant, and where the distance from the centre of the circle to the origin is greater than its radius.
To find a center in a quadrant?
It is not possible. A quadrant extends infinitely far in two directions and so has no centre.
What is the equation of a circle having a diameter with endpoints -3 1 and 5 7?
The equation works out as: (x-1)2+(y-4)2 = 25 whereas (1, 4) is the circle's centre and 25 is the radius2
What is an equation of the circle whose diameter has endpoints -3 1 and 5 -2?
The equation works out as: (x-1)2+(y+0.5)2 = 18.25 Equation of a circle: (x-a)2+(y-b)2 = radius2 whereas a and b are the coordinates of the circle's centre
What is the radius of a circle with a 3cm diameter?
The radius would be HALF the diameter, making the answer 1.5cm ! The diameter of a circle is the distance across it, passing through the centre. The radius is the distance from the centre to the edge.
What is the midpoint of the circle?
It is its centre or the midpoint of its diameter.
What is the equation of a circle whose diameter's end points are at 2 -3 and 8 7?
The mid point of the diameter is the circle's centre: Mid point of (2, -3) and (8, 7) is ((2 + 8)/2, (-3 + 7)/2) = (5, 2) The radius is half the diameter, but as the equation for a circle requires the radius squared: radius = diameter/2 → radius² = diameter² / 4 Diameter (and diameter²) can be found using Pythagoras: diameter² = change_in_x² + change_in_y² = (8 - 2)² + (7 - -3)² = 6² + 10² = 136 → radius² = 136/4 = 34 Circle with centre (X, Y) and radius r has equation: (x - X)² + (y - Y)² = r² → (x - 5)² + (y - 2)² = 34 → x² -10x + 25 + y² - 4y + 4 = 34 → x² + y² - 10x - 4x - 5 = 0
Why is the radius of the circle half the diameter?
The radius of a circle is the distance from the centre to the rim. The diameter is the distance fron rim to rim passing through the centre point. It therefore follows that the radius is half the diameter
If 5 7 and 9 3 are the end point of a diameter of acirclethen the centre ofthecircleis?
End points of diameter: (5, 7) and (9, 3) Midpoint of diameter which is the centre of circle: (7, 5)
