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the general equation of the circle is

(x-a)^2+(y-b)^2=r^2

where (a,b) is the center of the circle.

r is the radius of the circle

substituting the given values,

(x+4)^2+(y-3)^2=6^2

x^2+y^2+8x-6y+16+9=36

x^2+y^2+8x-6y=11

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Q: What is the equation of the circle with center -4 and 3 and radius 6?
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