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What is the equation of a circle whose center is at the origin and whose radius is 16?
(x-0)² + (y-0)² = r²
What is the equation of a circle with center 9 and -5 and radius 4?
(x - 9)2 + (y + 5)2 = 16
Which is an equation of a circle with center ( 2 7 ) and radius 4?
It is: (x-2)^2 +(y-7)^2 = 16
What is the center and radius of a circle described by the equation x2 y2 8x 4y 16 0?
To find the center and radius of the circle given by the equation (x^2 + y^2 - 8x - 4y - 16 = 0), we first rewrite it in standard form. Completing the square for both (x) and (y) gives us ((x - 4)^2 + (y - 2)^2 = 36). Thus, the center of the circle is at ((4, 2)) and the radius is (6) (since (r = \sqrt{36})).
What is the equation of a circle centered at the origin with a radius of 4?
x² + y² = 16.
What is the equation of a circle whose center is at the origin and whose radius is 16?
(x-0)² + (y-0)² = r²
What is the equation of a circle with center (-35)and radius 4?
It is: (x+3)^2 + (y-5)^2 = 16
The equation of a circle centered at the origin is x2 plus y2 16. What is the radius of the circle?
If that equals 16 then the radius is 4
What is the center and radius of the circle with equation ( x 5)2 ( y 3) 2 16?
If you mean: (x+5)^2 + (y+3)^2 = 16 Then its center is at (-5, -3) and its radius is 4
What is the equation of a circle with center 9 and -5 and radius 4?
(x - 9)2 + (y + 5)2 = 16
Which is an equation of a circle with center ( 2 7 ) and radius 4?
It is: (x-2)^2 +(y-7)^2 = 16
How do you graph the equation x squared plus y squared equals 16?
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
This circle is centered at the origin and the length of its radius is 4 What is the equation of the circle?
x2 + y2= 16
The equation for the circle below is x2 plus y2 16. What is the length of the circle's radius?
4
If the radius of a circle is 8 what is the diameter?
If the radius of a circle is 8, then the diameter is 16. The diameter of a circle is two times of a radius The equation would be d = 2r so plugging in 8 for r, the equation would become d = 2(8) Therefore d is 16.
What is the center and radius of a circle described by the equation x2 y2 8x 4y 16 0?
To find the center and radius of the circle given by the equation (x^2 + y^2 - 8x - 4y - 16 = 0), we first rewrite it in standard form. Completing the square for both (x) and (y) gives us ((x - 4)^2 + (y - 2)^2 = 36). Thus, the center of the circle is at ((4, 2)) and the radius is (6) (since (r = \sqrt{36})).
What is the standard form of the equation of a circle with center (2 3) and radius 4 units?
(x-2)^2 +(y-3)^2 = 16
