center 5,-3 radius 4
(x-0)² + (y-0)² = r²
It is: (x-2)^2 +(y-7)^2 = 16
(x - 9)2 + (y + 5)2 = 16
x² + y² = 16.
The radius is the line from the center to the outside of the circle, therefore the width of a circle is twice the radius. 2 x 8 feet =16 feet
(x-0)² + (y-0)² = r²
It is: (x+3)^2 + (y-5)^2 = 16
If that equals 16 then the radius is 4
If you mean: (x+5)^2 + (y+3)^2 = 16 Then its center is at (-5, -3) and its radius is 4
(x - 9)2 + (y + 5)2 = 16
It is: (x-2)^2 +(y-7)^2 = 16
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
x2 + y2= 16
4
If the radius of a circle is 8, then the diameter is 16. The diameter of a circle is two times of a radius The equation would be d = 2r so plugging in 8 for r, the equation would become d = 2(8) Therefore d is 16.
(x-2)^2 +(y-3)^2 = 16
x² + y² = 16.