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y=(-4)

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14y ago

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Related Questions

Is y-4 a horizontal or vertical line?

y - 4 is not an equation so does not form a line. y = 4 is a horizontal line as every co-ordinate has the y value of 4.


What is the equation of the horizontal line that passes through the point (9-4)?

Assuming the point is (9, -4), the equation is y = -4.


What equation always equals 5?

The equation of a vertical line x = 5 or the equation of a horizontal line y = 5.


The equation y - 4 equals 0 represents a vertical line?

No. It represents a horizontal line.


What is a slope of line y equals -4?

Since the equation y = -4 represents a horizontal line, then the slope of the line is 0.


Is y-4 equals 0 a linear equation?

yes because linear means straight line and that equation is a perfect horizontal line.


What is the equation for the line -4 -8 and that's horizontal?

4


Determine the point at which the graph of the function has a horizontal tangent line for the equation?

For the equation (9x^2)/(x^2+4)


What is the equation for a horizontal line?

y = 4 y = -3 etc. Replace the number to the right with any convenient number. For example, in the first equation, the line is 4 units above the x-axis.


What is the equation of the vertical line that passes through the point 0-4?

The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0


How do you determine the equation of a horizontal line that passes through negative 2 4?

I will assume you mean the line passes through (0, -24).The equation of a line is y=mx+cSince the line is horizontal, we know m is 0. Since m is zero, the x term disappears, leaving us with:y = cSince we know c (the y-intercept) to be -24, the equation of this line is simply:y = -24


Which line is perpendicular to x-3 and goes through the point (0-4)?

To find the line perpendicular to (x - 3), we first note that (x - 3) represents a vertical line, so a line perpendicular to it would be horizontal. The equation of a horizontal line that passes through the point ((0, -4)) is (y = -4). Thus, the line perpendicular to (x - 3) and passing through ((0, -4)) is (y = -4).