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What is the equation for the line -4 -8 and that's horizontal?
Wiki User
∙ 11y ago
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Anais Greenfelder
Wiki User
∙ 11y agoEquation of a straight line: y = mx+c whereas m is the slope and c is the y intercept
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Is y-4 a horizontal or vertical line?
y - 4 is not an equation so does not form a line. y = 4 is a horizontal line as every co-ordinate has the y value of 4.
The equation y - 4 equals 0 represents a vertical line?
No. It represents a horizontal line.
What is a slope of line y equals -4?
Since the equation y = -4 represents a horizontal line, then the slope of the line is 0.
Is y-4 equals 0 a linear equation?
yes because linear means straight line and that equation is a perfect horizontal line.
Determine the point at which the graph of the function has a horizontal tangent line for the equation?
For the equation (9x^2)/(x^2+4)
What is the equation of the horizontal line that has a y-intercept of -4?
y=(-4)
Is y-4 a horizontal or vertical line?
y - 4 is not an equation so does not form a line. y = 4 is a horizontal line as every co-ordinate has the y value of 4.
What is the equation of the horizontal line that passes through the point (9-4)?
Assuming the point is (9, -4), the equation is y = -4.
What equation always equals 5?
The equation of a vertical line x = 5 or the equation of a horizontal line y = 5.
The equation y - 4 equals 0 represents a vertical line?
No. It represents a horizontal line.
What is a slope of line y equals -4?
Since the equation y = -4 represents a horizontal line, then the slope of the line is 0.
Is y-4 equals 0 a linear equation?
yes because linear means straight line and that equation is a perfect horizontal line.
Determine the point at which the graph of the function has a horizontal tangent line for the equation?
For the equation (9x^2)/(x^2+4)
What is the equation of the vertical line that passes through the point 0-4?
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
What is the equation for a horizontal line?
y = 4 y = -3 etc. Replace the number to the right with any convenient number. For example, in the first equation, the line is 4 units above the x-axis.
How do you determine the equation of a horizontal line that passes through negative 2 4?
I will assume you mean the line passes through (0, -24).The equation of a line is y=mx+cSince the line is horizontal, we know m is 0. Since m is zero, the x term disappears, leaving us with:y = cSince we know c (the y-intercept) to be -24, the equation of this line is simply:y = -24
Will 2y plus 3 equals 4 graph a horizontal equation?
2Y + 3 = 4 2Y = 4 - 3 Y = 2 - 3/2 Y = 4/2 - 3/2 Y = 1/2 ---------------------- This is a horizontal equation where a line runs from negative infinity to positive infinity at the above.
