-5x-2y=10
To find the xy-trace, set z = 0 in the equation -5x - 2y - 3z = 10. Simplifying, we get -5x - 2y = 10. This is the equation of the xy-trace for the given plane.
5x 2y = 10
The equation is -2y + 16 = 10
Let's say that 5x + 2y + 3z = 10 is a line (that lives in a three dimensional space. When we let z = 0, the given line is projected on the xy-plane, and it will cut both x- and y-axis. So the equation of the trace line is 5x + 2y = 10. The line cut the x-axis at x = 2, and the y-axis at y = 5.
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Im guessing that the equation is 7x - 2y +3z= 19 so the answer is 7x + 3z= 19
5x - 2y = 10 2y = 5x - 10 y = 2.5x - 5......which is the equation in slope intercept form.
3x + 2y = 8 This is an equation. It could be the equation of a line.
7x-2y=10 -2y=10-7x y=-5+(7/2)x y=(7/2)x-5 (Final answer)
Multiply first equation by 2: 4x - 2y = 20 Subtract second equation: x = 12, so y = 14.
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
Simultaneous suggests at least two equations.