If you mean: 3x+2y = 16 then it is y = -1.5x+8
x+2y=8 Here you must add the expressions (2y - 2y = 0) 3x-2y=8 4x=16 Now you are left with a multiple of x so you can simply divide by 4 x=4 on both sides of the = 4+2y=8 Now you substitute x=4 into one of the original equations to find y 2y=4 y=2 Hope this helped.
The slope is 3. --------------------- 2y = 6x +8 /2 /2 /2 y = 3x + 4 Now that it's in y = mx + b form, m = slope, m= 3
x = 4y 3x - 2y = 20 Substituting the value of x into the second equation, 3*(4y) - 2y = 20 ie 12y - 2y = 20 or 10y = 20 so that y = 2 Then x = 4y = 4*2 = 8. So (x , y) = (8 , 2)
3x+11+5x=75(add 5x and 3x) 8x+11=75(-11) 8x=64(/ 8) x=8(ANSWER)
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
Well lets see: 2y = 6x+8 y=3x+4 does not equal y=3x+6 So they are not the same.
(-2, 4)
Both of them are equations!The solution is (x, y) = (2, 1).
3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
Multiply the first equation by -3
-3x + 2y = 8To get into slope intercept, we must set the equation equal to y2y = 3x + 8y = 3/2x + 8/2y = 3/2x + 4
If you mean: 3x+2y = 16 then it is y = -1.5x+8
The values are: x = -6 and y = 10
3x + 2y = 5x + 2y = 7Subtract (2) from (1) to give: 3x - x + 2y - 2y = 5 - 7→ 2x = -2→ x = -1Substitute for x in (1)3(-1) + 2y = 5→ -3 + 2y = 5→ 2y = 8→ y = 4Substitute for x and y in (2) to check answer:x + 2y = -1 +2(4) = -1 + 8 = 7 as required. Thus:x = -1y = 4
3x + 2y = 4; 2x - 2y = 16 Add; 5x = 20 so x = 4 and y is therefore -4
3X - 2Y = - 16 - 2Y = - 3X - 16 Y = (3/2)X + 8 ==============slope intercept form