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x-2/3 = 0

x - 5/7 = 0

(x-2/3)(x-5/7) = 0

x^2 -2/3(x) -5/7(x) + 10/21 = 0

x^2 -14/21(x) - 15/21(x) +10/21 = 0

x^2 -29/21(x) +10/21 = 0

Another Answer:-

If: x = 2/3 and x = 5/7

Then: (3x-2)(7x-5) = 0

Multiplying out the brackets: 21x2-29x+10 = 0 which is the equation.

Check using the quadratic equation formula: x = 2/3 and x = 5/7

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Q: What is the equation whose solutions are x equals 2 over 3 and x equals 5 over 7 showing work?
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