y=1.33x-4.68
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean point of (1, 4) and slope of -10 then y = -10x+14
To find the point-slope equation of the line with a slope of 2 and passing through the point (3, 10), we can use the point-slope formula: (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is the point. Plugging in the values, we get (y - 10 = 2(x - 3)). Simplifying this, the point-slope equation is (y - 10 = 2x - 6) or (y = 2x + 4).
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
The slope-intercept form of a line is given by the equation ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope ( m = -1 ) and a point (-10, -6), we can substitute these values into the equation to find ( b ): [ -6 = -1(-10) + b \implies -6 = 10 + b \implies b = -16. ] Thus, the slope-intercept form of the line is ( y = -x - 16 ).
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean point of (1, 4) and slope of -10 then y = -10x+14
It is: y = -10x+14
To find the point-slope equation of the line with a slope of 2 and passing through the point (3, 10), we can use the point-slope formula: (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is the point. Plugging in the values, we get (y - 10 = 2(x - 3)). Simplifying this, the point-slope equation is (y - 10 = 2x - 6) or (y = 2x + 4).
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
To find the point-slope form of a linear equation, you first need the equation in slope-intercept form (y = mx + b) or at least identify a point and the slope. The equation you've provided, "4x y 10," seems incomplete or unclear. If you mean (4x + y = 10), you can rearrange it to (y = -4x + 10), giving a slope (m = -4). The point-slope form is then (y - y_1 = m(x - x_1)) where ((x_1, y_1)) is any point on the line, such as (0, 10).
It is: y = -10x+14
Point: (2, 4) Slope: -3 Equation: y = -3x+10
Point: (-3, 4) Slope: 2 Equation: y-4 = 2(x--3) => y = 2x+10
The equation is: y = 4x-22