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To find the point-slope form of a linear equation, you first need the equation in slope-intercept form (y = mx + b) or at least identify a point and the slope. The equation you've provided, "4x y 10," seems incomplete or unclear. If you mean (4x + y = 10), you can rearrange it to (y = -4x + 10), giving a slope (m = -4). The point-slope form is then (y - y_1 = m(x - x_1)) where ((x_1, y_1)) is any point on the line, such as (0, 10).
What else can I help you with?
How do you graph 2x 5y equals 10?
To graph the equation (2x + 5y = 10), first, rearrange it into slope-intercept form by solving for (y): (5y = -2x + 10) or (y = -\frac{2}{5}x + 2). This shows that the y-intercept is 2 (the point (0, 2)), and the slope is (-\frac{2}{5}), indicating a downward slope. Plot the y-intercept on the graph and use the slope to find another point by moving down 2 units and right 5 units, then draw a straight line through these points.
How do you write 5.9 in standard form?
It is 5.9*10^0 but there is little point in appending "*10^0".
What is 10 months in decimal form?
It is 10 months. There is no need for a decimal point, and trailing 0s are misleading.
What is the answer for slope 4-4 8-1 0-7 -4-10?
Slope = 0.75
What is expanded form of a decimal point?
The expanded form of a decimal point involves breaking down the decimal number into its individual place values. For example, the decimal point in the number 3.456 represents the tenths place. In expanded form, this number would be written as 3 + 4/10 + 5/100 + 6/1000. Each digit after the decimal point is divided by a power of 10 corresponding to its place value.
What is the point-slope form of a line with slope -3 that contains the point (10-1)?
The point-slope form of a line is given by the equation ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) is a point on the line. Given a slope of -3 and the point (10, -1), we can substitute these values into the formula: ( y - (-1) = -3(x - 10) ). This simplifies to ( y + 1 = -3(x - 10) ), or ( y + 1 = -3x + 30 ). Thus, the point-slope form is ( y + 1 = -3(x - 10) ).
What is the slope intercept form of the equation for the line that passes through the point (-10-6) and has a slope of -1?
The slope-intercept form of a line is given by the equation ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope ( m = -1 ) and a point (-10, -6), we can substitute these values into the equation to find ( b ): [ -6 = -1(-10) + b \implies -6 = 10 + b \implies b = -16. ] Thus, the slope-intercept form of the line is ( y = -x - 16 ).
What is the slope of the line below is 2. Use the coordinates (310) to find a point slope equation of the line.?
To find the point-slope equation of the line with a slope of 2 and passing through the point (3, 10), we can use the point-slope formula: (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is the point. Plugging in the values, we get (y - 10 = 2(x - 3)). Simplifying this, the point-slope equation is (y - 10 = 2x - 6) or (y = 2x + 4).
Find the equation of a line parallel to y - 5x 10 that passes through the point (3 10). (answer in slope-intercept form)?
If you mean: y=-5x+10 and the point (3, 10) then the parallel equation is y=-5x+25
What is the equation of the line that passes through 2 4 and 1 -3 in slope-intercept form?
(2,4) (1, -3) First, find the slope, which is change in y over change in x. from -3 to 4 is 7 from 1 to 2 is 1 The slope is 7. Using the point slope formula you can find it in slope-intercept form. point-slope is y-y1=m(x-x1) *Number 1's are subscripts and m=slope* [You use a point for y1 and x1] y- (-3) = 7 (x-1) y+3 = 7x - 7 y= 7x -10
What is the slope if the line 4X plus 2Yequals 10?
Need point slope form. Y = mX + c 4X + 2Y = 10 2Y = - 4X + 10 Y = - 2X + 5 ========= slope(m) = - 2 -------------------
How do you write -10 3 and -2 -5 in point slope form?
Points: (-10, 3) and (-2, -5) Slope: -1 Equation: y = -x-7
Write in point slope form the equation of a line that has a slope of -3 and passes through point (2 4) use y-y1m(x-x1)?
Point: (2, 4) Slope: -3 Equation: y = -3x+10
What is the point-slope equation of the line with slope -10 that goes through the point (14)?
If you mean point of (1, 4) and slope of -10 then y = -10x+14
What is the the equation of the line that passes through -3 4 with a slope of 2 in point slope form?
Point: (-3, 4) Slope: 2 Equation: y-4 = 2(x--3) => y = 2x+10
What is the point-slope equation of the line with slope -10 that goes through the point (1 4)?
If you mean point of (1, 4) and slope of -10 then y = -10x+14
What is the point slope equation of the line with slope -10 that goes through the point(14)?
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
