Q: What is the point-slope equation of the line with slope -10 that goes through the point 14?

Write your answer...

Submit

Still have questions?

Continue Learning about Algebra

If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14

If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63

If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14

If you mean: slope of -13 and point of (5, 7) then the equation is y = -13x+72

If you mean a slope of 2 and a point of (1, 4) then the equation is y = 2x+2

Related questions

That will depend on the value of the slope which has not been given.

If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14

If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63

If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14

If you mean: slope of -13 and point of (5, 7) then the equation is y = -13x+72

write an equation that has a slope 7 and passes through the point (2,17)

Point: (1, 4) Slope: -3 Equation: y = -3x+7

The point slope equation is (y - 9) = 5*(x - 4)

You can have infinitely many lines through one specific point, each with a different equation. If you want to have a general equation for ANY line that goes through that point, use the point-slope equation for a line, and use a variable for the slope.

It is: y = -10x+14

Slope: -13 Point: (5, 7) Equation: y = -13x+72 whereas -13 is the slope and 72 is the y intercept

Slope: -13 Point: (5, 7) Equation: y = -13x+72 whereas -13 is the slope and 72 is the y intercept