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Not all negative numbers are integers. Some are fractions.

Q: What is the error in saying that negatives numbers are integers?

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This is best solved by trial-and-error. If one set of consecutive even integers doesn't work, try a different set. Hint: The integers involved are fairly small.

You can find that out by trial-and-error, that is, experiment with different numbers. Or, you can call the first number "n", in which case the second number is "n+2", and you solve the equation:n + (n+2) = 32

You can find those by trial and error. You can also write an equation for the three consecutive integers, and solve it. If the first number is "n", the others are "n + 1" and "n + 2". By solving the equation for "n", you get the first of the three numbers.

It looks like you are asking how many combinations of 6 numbers are there in the 28 numbers 1 through 28. This is known as the number of combinations of 28 things taken 6 at a time. The answer is 28!/(6!22!) (n! means n factorial, which is the product of all the integers from 1 to n). I get 376,740 if I haven't made an error in arithmetic.

Related questions

The error is that 'tives' is not a word, it is the -suffix for words such as 'positives' and 'negatives'.

This is quickly solved by trial-and-error. Try multiplying two consecutive integers. If the result it too high, try again with lower numbers. If the result is too low, try again with higher numbers.

86

This is best solved by trial-and-error. If one set of consecutive even integers doesn't work, try a different set. Hint: The integers involved are fairly small.

Two consecutive numbers (pressumably integers) will always add up to an odd number, so this has no solution. If you mean "two consecutive even numbers" or "two consecutive odd numbers", you should quickly be able to find a solution by trial-and-error.

You can find that out by trial-and-error, that is, experiment with different numbers. Or, you can call the first number "n", in which case the second number is "n+2", and you solve the equation:n + (n+2) = 32

You can find those by trial and error. You can also write an equation for the three consecutive integers, and solve it. If the first number is "n", the others are "n + 1" and "n + 2". By solving the equation for "n", you get the first of the three numbers.

I cannot connect to my profile on Twitter. It keeps on saying error on page

1. Accept the 2 numbers 2. Add the 2 numbers3. Compare answer with 54. If answer is greater than 5 subtract with 5 else give a error message.

Negatives- -many more humans will become unemployed -they break down a lot (error out) -they might invade man kind -start wars Positives- -carry out physical task -faster than most humans

A common slang word for an error is "blunder" or "screw-up."

You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.