Q: The sum of 4 consecutive integers is -82 what are the integers?

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There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.

If n is the smallest of the four integers, their sum is 4n+6.

The greatest integer is 24.

118

The integers are -2, 0, 2 and 4.

Related questions

82, 84, 86, 88

I assume you wish to know which four consecutive even integers sum to 340. Let the smallest of the integers be x. Then the others are x+2, x+4 and x+6 and x + (x+2) + (x+4) + (x+6) = 340 iff 4x = 328 iff x = 82. So the integers are 82, 84, 86 and 88.

There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.

-4 and -5

If n is the smallest of the four integers, their sum is 4n+6.

4 and 5

There are four consecutive odd integers: 81, 83, 85 and 87.

-3,-4,-5

The greatest integer is 24.

118

The integers are -2, 0, 2 and 4.

Integers are a, a + 2 and a + 4. (a +(a + 2)) x (a + 2) + 3(a + 4) = 82 (2a + 2)(a + 2) + 3a + 12 = 82 2a2 + 6a + 4 + 3a + 12 - 82 = 0 2a2 + 9a - 66 = 0 which has no solutions in integers. Can you clarify the question, please?