There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
Because 6*8 = 48 and 48/8 = 6
The two integers are 6 and 7.
The four consecutive even integers are 4, 6, 8, 10. The product of 8 and 10 is 80. Algebraically, the equation to find the four integers is : [x + (x+2) + (x+4) + (x+ 6)]/4 = 7 (4x + 12) / 4 = 7 x + 3 = 7 x = 4 x+2 = 6 // x+4 = 8 // x+6 = 10
Call the two consecutive integers n and n+1. Their product is n(n+1) or n2 +n. For example if the integers are 1 and 2, then n would be 1 and n+1 is 2. Their product is 1x2=2 of course which is 12 +1=2 Try 2 and 3, their product is 6. With the formula we have 4+2=6. The point of the last two examples was it is always good to check your answer with numbers that are simple to use. That does not prove you are correct, but if it does not work you are wrong for sure!
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
They are 6, 8, 10 and 12.
They are -7 and -5.
Because 6*8 = 48 and 48/8 = 6
48 = 6 x 8, so the smaller is 6.
The numbers are 6 and 8.
The two integers are 6 and 7.
They are 6 times 8 = 48
The four consecutive even integers are 4, 6, 8, 10. The product of 8 and 10 is 80. Algebraically, the equation to find the four integers is : [x + (x+2) + (x+4) + (x+ 6)]/4 = 7 (4x + 12) / 4 = 7 x + 3 = 7 x = 4 x+2 = 6 // x+4 = 8 // x+6 = 10
Smaller number is '6'
The product of 2 consecutive positive number is 48. Find the 2 numbers
The four even integers are 6, 8, 10, 12. 6 x 8 = 48 10 x 12 = 120 120 - 48 = 72