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This is quickly solved by trial-and-error. Try multiplying two consecutive integers. If the result it too high, try again with lower numbers. If the result is too low, try again with higher numbers.
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Why is the product of any consecutive integers divisible by 6?
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
How do you prove that the product of two consecutive even integers is divisible by 8?
Because 6*8 = 48 and 48/8 = 6
If the sum of two consecutive integers is thirteen find the smaller integer.?
The two integers are 6 and 7.
If the average of four consecutive integers even integers is 7 what is the product of the two greatest of these integers?
The four consecutive even integers are 4, 6, 8, 10. The product of 8 and 10 is 80. Algebraically, the equation to find the four integers is : [x + (x+2) + (x+4) + (x+ 6)]/4 = 7 (4x + 12) / 4 = 7 x + 3 = 7 x = 4 x+2 = 6 // x+4 = 8 // x+6 = 10
How do you find the product of consecutive integers?
Call the two consecutive integers n and n+1. Their product is n(n+1) or n2 +n. For example if the integers are 1 and 2, then n would be 1 and n+1 is 2. Their product is 1x2=2 of course which is 12 +1=2 Try 2 and 3, their product is 6. With the formula we have 4+2=6. The point of the last two examples was it is always good to check your answer with numbers that are simple to use. That does not prove you are correct, but if it does not work you are wrong for sure!
Why is the product of any consecutive integers divisible by 6?
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
Find 4 consecutive even integers where the product of the two smaller numbers is 72 less than the product of the larger two integers?
They are 6, 8, 10 and 12.
What two consecutive odd integers product is 107 more than 6 times its sum?
They are -7 and -5.
How do you prove that the product of two consecutive even integers is divisible by 8?
Because 6*8 = 48 and 48/8 = 6
The product of two positive consecutive even integers is 48 what is the smaller number?
48 = 6 x 8, so the smaller is 6.
The product of 2 consecutive even integers is 48?
The numbers are 6 and 8.
If the sum of two consecutive integers is thirteen find the smaller integer.?
The two integers are 6 and 7.
The product of 2 positive consecutive even integers is 48.?
They are 6 times 8 = 48
If the average of four consecutive integers even integers is 7 what is the product of the two greatest of these integers?
The four consecutive even integers are 4, 6, 8, 10. The product of 8 and 10 is 80. Algebraically, the equation to find the four integers is : [x + (x+2) + (x+4) + (x+ 6)]/4 = 7 (4x + 12) / 4 = 7 x + 3 = 7 x = 4 x+2 = 6 // x+4 = 8 // x+6 = 10
The product of 2 consecutive even integers is 48 what is the smaller number?
Smaller number is '6'
The product of 2 positive consecutive even integers is 48 What is the smaller number?
The product of 2 consecutive positive number is 48. Find the 2 numbers
Find 4 consecutive integers even integers where the product of the smaller number is 72 less than the product of the two larger numbers?
The four even integers are 6, 8, 10, 12. 6 x 8 = 48 10 x 12 = 120 120 - 48 = 72
