7 - ( 3 ÷ v )
7 minus the quotient of 3 and v
The expression for the product of ( m ) and 5 minus the quotient of ( t ) and 7 can be written mathematically as ( 5m - \frac{t}{7} ). This represents the result of multiplying ( m ) by 5 and then subtracting the result of dividing ( t ) by 7.
It is: 3v-7
It means: 10 minus 3 = 7
It is suppose to be k/3 minus 7
It is 1 - r/7
7 minus the quotient of 3 and v
The expression for the product of ( m ) and 5 minus the quotient of ( t ) and 7 can be written mathematically as ( 5m - \frac{t}{7} ). This represents the result of multiplying ( m ) by 5 and then subtracting the result of dividing ( t ) by 7.
It is: 3v-7
3 + x/7 Normally an expression like this forms part of an equation such as y = 3 + x/7
It means: 10 minus 3 = 7
3 + 52 / 33 - 23 = 28/4 = 7
It is suppose to be k/3 minus 7
Well, isn't that just a happy little math problem we have here! To find the answer, you first need to divide 3 by v to get the quotient, and then subtract that from 7. Remember, there are no mistakes in math, just happy little accidents waiting to be corrected!
The algebraic expression for "4 decreased by the quotient of a number and 7" can be represented as 4 - (x/7), where x is the variable representing the number. The expression first calculates the quotient of the number and 7 by dividing x by 7, and then subtracts that quotient from 4. This expression captures the mathematical operation described in the question.
2x + 7
5m-t/7