7 - ( 3 ÷ v )
7 minus the quotient of 3 and v
The expression for the product of ( m ) and 5 minus the quotient of ( t ) and 7 can be written mathematically as ( 5m - \frac{t}{7} ). This represents the result of multiplying ( m ) by 5 and then subtracting the result of dividing ( t ) by 7.
It is: 3v-7
It means: 10 minus 3 = 7
It is suppose to be k/3 minus 7
It is 1 - r/7
7 minus the quotient of 3 and v
The expression for the product of ( m ) and 5 minus the quotient of ( t ) and 7 can be written mathematically as ( 5m - \frac{t}{7} ). This represents the result of multiplying ( m ) by 5 and then subtracting the result of dividing ( t ) by 7.
It is: 3v-7
3 + x/7 Normally an expression like this forms part of an equation such as y = 3 + x/7
It means: 10 minus 3 = 7
3 + 52 / 33 - 23 = 28/4 = 7
It is suppose to be k/3 minus 7
The algebraic expression for "4 decreased by the quotient of a number and 7" can be represented as 4 - (x/7), where x is the variable representing the number. The expression first calculates the quotient of the number and 7 by dividing x by 7, and then subtracts that quotient from 4. This expression captures the mathematical operation described in the question.
Well, isn't that just a happy little math problem we have here! To find the answer, you first need to divide 3 by v to get the quotient, and then subtract that from 7. Remember, there are no mistakes in math, just happy little accidents waiting to be corrected!
2x + 7
5m-t/7