x(5x + 7)
(5x + 2)(x + 1)
True.
5x2+ 7x + 2 = (x + 1)(5x + 2).
5x2+7x = 12 5x2+7x-12 = 0 (5x+12)(x-1) = 0 x = -12/5 or x = 1
5x2 + 3x - 1 does not have rational factors.
I am assuming this is: .2x4 - 5x2 - 7x, which would be a Quartic Polynomial.
(3b + 7x)(3b + 7x) or (3b + 7x)2
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-7 plus or minus the square root of -371) divided by 10x = -0.7 + 1.9261360284258224ix = -0.7 - 1.9261360284258224iwhere i is the square root of negative one.
5x2 + 20x = 5x (x + 4)
5x2-46x+9 = (5x-1)(x-9)
5x(x+3)
5x2-18x+9 = (5x-3)(x-3)