5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
5x2+14x-3 -15. 15*-15x2-x+15x-3[5xx x] [3*5x 3]x(5x-1)+3(5x-3)Answer: (5x-1)(x+3)
18x2 + 15x + 2 = (3x + 2)(6x + 1)
(5x - 1)(x + 3)5x2 + 14x - 3= 5x2 + 15x - x - 3= 5x(x + 3) - 1(x + 3)= (5x - 1)(x + 3)
5x2-46x+9 = (5x-1)(x-9)
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
5x2+14x-3 -15. 15*-15x2-x+15x-3[5xx x] [3*5x 3]x(5x-1)+3(5x-3)Answer: (5x-1)(x+3)
5x2 + 14x - 3 let 14x = 15x - x=5x 2 + 15x - x - 3 factor out 5x and -1 = 5x(x + 3) - 1(x + 3) factor (x + 3) = (x + 3)(5x - 1)
You can't factor it
5x2 + 3x - 1 does not have rational factors.
18x2 + 15x + 2 = (3x + 2)(6x + 1)
(5x - 1)(x + 3)5x2 + 14x - 3= 5x2 + 15x - x - 3= 5x(x + 3) - 1(x + 3)= (5x - 1)(x + 3)
5x2-46x+9 = (5x-1)(x-9)
5x2 + 20x = 5x (x + 4)
9xy2 - 24xy + 15x
x(5x + 7)
I'm pretty sure you didn't write down the expression to be factored correctly. If you can't do that, neither you nor anybody else will be able to factor your expression.