5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
5x2+14x-3 -15. 15*-15x2-x+15x-3[5xx x] [3*5x 3]x(5x-1)+3(5x-3)Answer: (5x-1)(x+3)
(5x - 1)(x + 3)5x2 + 14x - 3= 5x2 + 15x - x - 3= 5x(x + 3) - 1(x + 3)= (5x - 1)(x + 3)
18x2 + 15x + 2 = (3x + 2)(6x + 1)
5x2-46x+9 = (5x-1)(x-9)
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
5x2+14x-3 -15. 15*-15x2-x+15x-3[5xx x] [3*5x 3]x(5x-1)+3(5x-3)Answer: (5x-1)(x+3)
5x2 + 14x - 3 let 14x = 15x - x=5x 2 + 15x - x - 3 factor out 5x and -1 = 5x(x + 3) - 1(x + 3) factor (x + 3) = (x + 3)(5x - 1)
You can't factor it
5x2 + 3x - 1 does not have rational factors.
18x2 + 15x + 2 = (3x + 2)(6x + 1)
(5x - 1)(x + 3)5x2 + 14x - 3= 5x2 + 15x - x - 3= 5x(x + 3) - 1(x + 3)= (5x - 1)(x + 3)
5x2-46x+9 = (5x-1)(x-9)
5x2 + 20x = 5x (x + 4)
9xy2 - 24xy + 15x
I'm pretty sure you didn't write down the expression to be factored correctly. If you can't do that, neither you nor anybody else will be able to factor your expression.
x(5x + 7)