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Q: What is the factorization of the trinomial below2x2 plus 21x plus 49?

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(2x+7)(x+7)

2x2 + 21x + 49 = 2x2 +14x +7x + 49 = 2x(x + 7) + 7(x + 7) = (2x + 7)(x + 7)

10x2y2 + 8xy2 - 210y2 = 2y2(5x2 + 4x - 105) = 2y2(5x2 + 25x - 21x - 105) = 2y2(x + 5)(5x - 21).

2x2 + 21x + 49 = (2x + 7)(x + 7)

2x2 + 21x + 49= 2x2 + 14x + 7x + 49= 2x(x + 7) + 7(x + 7)= (x + 7)(2x + 7)

14xy -21x+7

Presumably all the terms are positive? (2x+7(x+7)

21x + 9 = 180 21x = 180 - 9 21x = 171 x = 171/21 x = 8.143

3 * 7 * x No exponents necesary

21x+452 = 32-84x 21x+84x = 32-452 105x = -420 x = -4

234 it is not the answer

i hope you mean (2x^2 + 21x + 49) you cant solve it its already in its lowest possible form

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