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What is the factorization of this trinomial 2x2 plus 21x plus 49?
2x2 + 21x + 49 = 2x2 +14x +7x + 49 = 2x(x + 7) + 7(x + 7) = (2x + 7)(x + 7)
What is the factorization of 2 times x squared plus 21x plus 49?
2x2 + 21x + 49= 2x2 + 14x + 7x + 49= 2x(x + 7) + 7(x + 7)= (x + 7)(2x + 7)
What is the factor tree method of 196?
196 98x2=196 49x2=98 7x7=49 2x2&7x7
Is this trinomial a trinomial square x2 plus 14x plus 49?
x2+14x+49 = (x+7)(x+7) when factored
How do you do 21x2 plus 55x plus 14?
To simplify the expression (21x^2 + 55x + 14), you can factor it, if possible. First, look for two numbers that multiply to (21 \times 14 = 294) and add up to (55). The numbers (49) and (6) fit this requirement, allowing you to rewrite the expression as (21x^2 + 49x + 6x + 14). Then, factor by grouping to get ((21x^2 + 49x) + (6x + 14) = 7x(3x + 7) + 2(3x + 7) = (3x + 7)(7x + 2)).
What is the factorization of the trinomial below2x2 plus 21x plus 49?
2x2+21x+49 = (2x+7)(x+7)
What is the factorization of this trinomial 2x2 plus 21x plus 49?
2x2 + 21x + 49 = 2x2 +14x +7x + 49 = 2x(x + 7) + 7(x + 7) = (2x + 7)(x + 7)
What is the factorization of the trinomial below 2x2 plus 21x plus 49?
(2x+7)(x+7)
What is the factorization of 2 times x squared plus 21x plus 49?
2x2 + 21x + 49= 2x2 + 14x + 7x + 49= 2x(x + 7) + 7(x + 7)= (x + 7)(2x + 7)
What is the factorization of 2.x square plus 21.x plus 49?
2x2 + 21x + 49 = (2x + 7)(x + 7)
How do you factor 35x 63y?
7(5x + 9y)
Find the value of c for which the roots of 2x2-21x c0?
2x^2 - 21x + c = 0 x^2 - 21x/2 + c/2 = 0 (x + a)(x + 2a)= x^2 - 21x/2 + c/2 x^2 + 3a + 2a^2 3a = -21/2 ------> a = -7/2 2a^2 = c/2 ---> 49/2 = c/2 ---> c = 49
2x square plus 21x plus 49?
i hope you mean (2x^2 + 21x + 49) you cant solve it its already in its lowest possible form
What is the factor tree method of 196?
196 98x2=196 49x2=98 7x7=49 2x2&7x7
What is 21x plus 49 factorised?
7(3x+7)
Is this trinomial a trinomial square x2 plus 14x plus 49?
x2+14x+49 = (x+7)(x+7) when factored
How do you do 21x2 plus 55x plus 14?
To simplify the expression (21x^2 + 55x + 14), you can factor it, if possible. First, look for two numbers that multiply to (21 \times 14 = 294) and add up to (55). The numbers (49) and (6) fit this requirement, allowing you to rewrite the expression as (21x^2 + 49x + 6x + 14). Then, factor by grouping to get ((21x^2 + 49x) + (6x + 14) = 7x(3x + 7) + 2(3x + 7) = (3x + 7)(7x + 2)).
