x(x + 9)(x + 5)
3x3 - 24x2 + 45x = 3x*(x2 - 8x + 15) = 3x*(x - 3)*(x - 5)
3x3 - 24x2 + 45x = 3x(x2 - 8x + 15) = 3x(x2 - 3x - 5x + 15) = 3x[ x(x - 3) - 5(x - 3) ] = 3x(x - 5)(x - 3)
X3 - 4X2 - 45XX(X2 - 4X - 45)=============X is only common factor here.
(5x+4)(9x+9) FOIL First (5x*9x=45x**2) Outside (5x*9=45x) Inside (4*9x=36x) Last (4*9=36) 45x**2+45x+36x+36 45x**2+81x+36 9(5x**2+9x+4x)
It is an algebraic expression that can be simplified to: 45x -16
(9x)2 +9x/(45x)2 +81= 9+9x/86
45x
88x+33=45x*56 88x+33=2520x 33=2432x x=0.013569
3x(x - 5)(x - 3)
If: -45x-6 = 2 Then: -45x = 2+6 => -45x = 8 And: x = -8/45
To factor the polynomial ( 125x^3 + 45x ), first, we can factor out the greatest common factor, which is ( 5x ). This gives us ( 5x(25x^2 + 9) ). The quadratic ( 25x^2 + 9 ) cannot be factored further using real numbers since it does not have real roots. Therefore, the complete factorization is ( 5x(25x^2 + 9) ).
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