3x3-18x2+24x=3x(x2-6x+8)=3x(x-4)(x-2)
Start by looking for a common factor. Separate this factor, then factor the remaining polynomial.
-3x3 - 6x2 + 189x = -3x(x2 + 2x - 63) = -3x(x + 9)(x - 7)
x - 2 = 0 if x = 2 So put x = 2 into 3x3 - 2x + 2 ie 24 - 4 + 2 = 22
3 to the 2nd power or 32
3x3 - 24x2 + 45x = 3x(x2 - 8x + 15) = 3x(x2 - 3x - 5x + 15) = 3x[ x(x - 3) - 5(x - 3) ] = 3x(x - 5)(x - 3)
3x3-18x2+24x=3x(x2-6x+8)=3x(x-4)(x-2)
3x(x - 5)(x - 3)
if its 3x3 - 2x + 1 then its a cubic trinomial
3x(x2 + 2x - 4)
3X3 + 6X2 - 24X3X(X2 + 2X - 8)3X(X + 4)(X - 2)================assuming that last term was - 24X
3x3
3x3=99+2=1111+3=14=14
360=2^3x3^2x5
what kind of polynomial is shown 3x3+x+1
3x3+12x = 3x(x2+4)
Given 3x3 + 4x2 +x + 7 is divided by x2 + 1, find the results: