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Q: What is the factorization of the trinomial 3x3 - 24x2 plus 45x?

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3x3-18x2+24x=3x(x2-6x+8)=3x(x-4)(x-2)

Start by looking for a common factor. Separate this factor, then factor the remaining polynomial.

-3x3 - 6x2 + 189x = -3x(x2 + 2x - 63) = -3x(x + 9)(x - 7)

x - 2 = 0 if x = 2 So put x = 2 into 3x3 - 2x + 2 ie 24 - 4 + 2 = 22

3 to the 2nd power or 32

Related questions

3x3 - 24x2 + 45x = 3x(x2 - 8x + 15) = 3x(x2 - 3x - 5x + 15) = 3x[ x(x - 3) - 5(x - 3) ] = 3x(x - 5)(x - 3)

3x3-18x2+24x=3x(x2-6x+8)=3x(x-4)(x-2)

3x(x - 5)(x - 3)

3x(x + 4)(x - 2)

if its 3x3 - 2x + 1 then its a cubic trinomial

3x^3 + 6x^2 - 24x = 3x*(x-2)*(x+4)

3x(x2 + 2x - 4)

3x(x2 + 2x - 4)

3x3

3x3

3X3 + 6X2 - 24X3X(X2 + 2X - 8)3X(X + 4)(X - 2)================assuming that last term was - 24X

3x3=99+2=1111+3=14=14

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