25mph
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
87.5mi/hr2
Do your own homework! The train travelling at the constant speed will still be doing 16ms after 10 seconds The other train adds 1m per second so, after 10 seconds it will have added 10, 10 + 8 = 18ms. It is going faster. or : you can find the final velocity : final velocity = vi+a(t) = 8+1(10) =18 m/s So Train B is faster.
A marble traveling at 3.0m/s starts to acceleration at 4.5m/s over a distance of 25m. what is the final speed of the marble?
On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get: 78.4m/s
the final velocity = initial velocity + acceleration x time; since acceleration is negative final velocity = 45 - 10x3 = 45 -30 = 15 mph
30mph
the final velocity = initial velocity + acceleration x time; since acceleration is negative final velocity = 45 - 10x3 = 45 -30 = 15 mph
Its 3.0 m/s acceleration = (final_speed − initial_speed) / time_interval Solve the above for "final speed." They give you all the other quantities, so just plug them in. (Remember that "deceleration" means the acceleration is negative.
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b.com final 2010 time table plz